Question

[Nguyễn Tú Anh]

                   Hộ tui nhá!! cảm Mơn nhiều nhiều!! Tìm x

1,x^2+8/9=41/36

2,(x-3)^2+-9/25=2/5*8/5

3, 3/11*22/6-(x-1)^2=7/16

4,1+(x+1)^3=37/64

5, (x-1/2)^2-9/16=1

6, 3-x/5-x=(-3/5)^2

                              Mơn nhìu nhìu nhìu nhìu nhìu nhìu nhìu nhìu nhìu nhìu nhìu nhìu!!!!!!!!!!!!!!!!!

Answer 1

[Nguyễn Minh Đăng]

1) \(x^2+\frac{8}{9}=\frac{41}{36}\)\(\Leftrightarrow x^2=\frac{1}{4}\Leftrightarrow x=\pm\frac{1}{2}\)

2) \(\left(x-3\right)^2+-\frac{9}{25}=\frac{2}{5}.\frac{8}{5}\)

\(\Leftrightarrow\left(x-3\right)^2=1\)

\(\Leftrightarrow\orbr{\begin{cases}x-3=1\\x-3=-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=4\\x=2\end{cases}}\)

3) \(\frac{3}{11}.\frac{22}{6}-\left(x-1\right)^2=\frac{7}{16}\)

\(\Leftrightarrow\left(x-1\right)^2=\frac{9}{16}\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=\frac{3}{4}\\x-1=-\frac{3}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{7}{4}\\x=\frac{1}{4}\end{cases}}\)

4) \(1+\left(x+1\right)^3=\frac{37}{64}\)

\(\Leftrightarrow\left(x+1\right)^3=-\frac{27}{64}\)

\(\Rightarrow x+1=-\frac{3}{4}\)

\(\Leftrightarrow x=-\frac{7}{4}\)

5) \(\left(x-\frac{1}{2}\right)^2-\frac{9}{16}=1\)

\(\Leftrightarrow\left(x-\frac{1}{2}\right)^2=\frac{25}{16}\)

\(\Leftrightarrow\orbr{\begin{cases}x-\frac{1}{2}=\frac{5}{4}\\x-\frac{1}{2}=-\frac{5}{4}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{7}{4}\\x=-\frac{3}{4}\end{cases}}\)

6) Bn ghi rõ đề nha mk ko hiểu 

Answer 2

[trinh quang huy]

6 ) \(\frac{3-x}{5-x}=\left(\frac{-3}{5}\right)^2\)

\(\frac{3-x}{5-x}=\frac{9}{25}\Leftrightarrow\frac{3-x}{5-x}-\frac{9}{25}\Leftrightarrow\frac{75-25x}{125-25x}-\frac{45-9x}{125-5x}=0\)

\(\Rightarrow\frac{75-25-45+9x}{125-25x}=0\Leftrightarrow5+9x=0\Leftrightarrow x=\frac{-5}{9}\)