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`#3107.101107`
a,
$2014^{15} . (2x - 60) = 2014^{16}$
$\Rightarrow 2x - 60 = 2014^{16} \div 2014^{15}$
$\Rightarrow 2x - 60 = 2014$
$\Rightarrow 2x = 2074$
$\Rightarrow x = 1037$
Vậy, `x = 1037`
b,
`x + 18 \div 3^2 = 5.4^2`
`\Rightarrow x + 18 \div 9 = 5.16`
`\Rightarrow x + 9 = 80`
`\Rightarrow x = 80 - 9`
`\Rightarrow x = 71`
Vậy, `x = 71`
c,
`7.(42 - x) = 5^3 + 134`
`\Rightarrow 7.(42 - x) = 125 + 134`
`\Rightarrow 7(42 - x) = 259`
`\Rightarrow 42 - x = 259 \div 7`
`\Rightarrow 42 - x = 37`
`\Rightarrow x = 42 - 37`
`\Rightarrow x = 5`
Vậy, `x = 5.`
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`@` `\text {Ans}`
`\downarrow`
`12 \div 6 + 2. 7`
`= 2 + 2.7`
`= 2.(1 + 7)`
`= 2.8`
`= 16`
`5. 4^2 - 36 \div 3^2`
`= 5. 16 - 36 \div 9`
`= 80 - 4`
`= 76`
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Giải:
Bài 1:
a) \(6^2\): 4 . 3 + 2 . \(5^2\)
= 36 : 4 . 3 + 2 . 25
= 27 + 50
= 77
77 = 7 . 11
b) 5 . \(4^2\) - 18 : \(3^2\)
= 5 . 16 - 18 : 9
= 80 - 2
= 78
78 = 2 .3 . 13
Bài 2:
a) Ta có: \(70⋮x\)
\(84⋮x\)
Do đó: \(x\inƯC\left(70;84\right)\)
\(\Leftrightarrow x\inƯ\left(14\right)\)
\(\Leftrightarrow x\in\left\{1;2;7;14\right\}\)
mà x>8
nên x=14
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\(m=\dfrac{2^7\cdot3^5+2^4\cdot3^9}{2^6\cdot3^5+2^3\cdot3^9}\)
\(m=\dfrac{2^4\cdot3^5\cdot\left(2^3+3^4\right)}{2^3\cdot3^5\cdot\left(2^3+3^4\right)}\)
\(m=\dfrac{2^4\cdot3^5}{2^3\cdot3^5}\)
\(m=\dfrac{2^4}{2^3}\)
\(m=2^{4-3}\)
\(m=2\)
\(=36:4\cdot3+104+210-\dfrac{18}{32}=341-\dfrac{9}{16}=\dfrac{5447}{16}\)