Question

[Nguyễn Hoàng Minh]

Giải phương trình:

1/ \(\frac{4x+7}{x-1}\)=\(\frac{12x+5}{3x+4}\)

2/\(\frac{5x-1}{3x+2}\) =\(\frac{5x-7}{3x-1}\)

3/\(\frac{x+1}{x-2}\) =\(\frac{1}{x^{2^{ }}-4}\)

Answer 1

[phan thị minh anh]

1. \(\left(4x+7\right)\left(3x+4\right)=\left(12x-5\right)\left(x-1\right)\)

\(12x^2+16x+21x+28=12x^2-12x-5x+5\)

\(12x^2+37x+28-12x^2+17x-5=0\)

54x+23=0

54x=-23

x=-23/54

Answer 2

[phan thị minh anh]

2. \(\left(5x-1\right)\left(3x-1\right)=\left(5x-7\right)\left(3x+2\right)\)

\(15x^2-5x-3x+1=15x^2+10x-21x-14\)

\(15x^2-8x+1-15x^2+11x+14=0\)

3x+15=0

3x=-15

x=-5