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11 tháng 1 2018

a ) \(\left(5x+7\right)\left(x-7\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{7}{5}\\x=7\end{matrix}\right.\)

b ) \(\left(x^2-1\right)\left(x+3\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(x+1\right)\left(x+3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-1\\x=-3\end{matrix}\right.\)

c )\(x^2-x-6=0\)

\(\Leftrightarrow x^2-3x+2x-6=0\)

\(\Leftrightarrow\left(x+2\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=3\end{matrix}\right.\)

d ) \(x^2+x-12=0\)

\(\Leftrightarrow x^2-4x+3x-12\)

\(\Leftrightarrow\left(x+3\right)\left(x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=4\end{matrix}\right.\)

e ) \(15\left(x+9\right)\left(x-3\right)\left(x+21\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-9\\x=3\\x=-21\end{matrix}\right.\)

g ) \(\left(x^2+1\right)\left(x^2+4x+4\right)=0\)

\(\Leftrightarrow\left(x^2+1\right)\left(x+2\right)^2=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x^2=-1\left(loại\right)\\x=-2\end{matrix}\right.\)

i ) \(x^4+2x^3-2x^2+2x-3=0\)

\(\Leftrightarrow x^4+3x^3-x^3-3x^2+x^2+3x-x-3=0\)

\(\Leftrightarrow x^3\left(x+3\right)-x^2\left(x+3\right)+x\left(x+3\right)-\left(x+3\right)=0\)

\(\Leftrightarrow\left(x^3-x^2+x-1\right)\left(x+3\right)=0\)

\(\Leftrightarrow\left(x^2+1\right)\left(x-1\right)\left(x+3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x^2=-1\left(loại\right)\\x=1\\x=-3\end{matrix}\right.\)

h) \(x^2+5x+6=0\)

\(\Leftrightarrow x^2+3x+2x+6=0\)

\(\Leftrightarrow\left(x+2\right)\left(x+3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=-3\end{matrix}\right.\)