Question

[Nguyễn Mạnh Ngọc]

Giải phương trình: a) 4x^4-9=0 b) √(9x-9) - √(x-1) = 8

Answer 1

[Lê Thị Thục Hiền]

a) \(4x^4-9=0\Leftrightarrow x^4=\dfrac{9}{4}\)\(\Leftrightarrow\left[{}\begin{matrix}x^2=\dfrac{3}{2}\\x^2=-\dfrac{3}{2}\left(vn\right)\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\sqrt{\dfrac{3}{2}}\\x=-\sqrt{\dfrac{3}{2}}\end{matrix}\right.\)

Vậy...

b) \(\sqrt{9x-9}-\sqrt{x-1}=8\left(đk:x\ge1\right)\)

\(\Leftrightarrow\sqrt{9\left(x-1\right)}-\sqrt{x-1}=8\)

\(\Leftrightarrow3\sqrt{x-1}-\sqrt{x-1}=8\)

\(\Leftrightarrow\sqrt{x-1}=4\)

\(\Leftrightarrow x=17\)(thỏa)

Vậy...

Answer 2

[Trần Minh Hoàng]

a) \(4x^4-9=0\Leftrightarrow\left(2x^2\right)^2=3^2\Leftrightarrow2x^2=3\Leftrightarrow x^2=\dfrac{3}{2}\Leftrightarrow x=\pm\sqrt{\dfrac{3}{2}}\)