Question

[Anh Lan]

Giải bất phương trình: |2x - 7| < x² + 2x + 2

Answer 1

[Nguyễn Việt Lâm]

TH1: \(\left\{{}\begin{matrix}2x-7\ge0\\2x-7< x^2+2x+2\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x\ge\dfrac{7}{2}\\x^2>-9\end{matrix}\right.\) \(\Rightarrow x\ge\dfrac{7}{2}\)

TH2: \(\left\{{}\begin{matrix}2x-7< 0\\7-2x< x^2+2x+2\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x< \dfrac{7}{2}\\x^2+4x-5>0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x< \dfrac{7}{2}\\\left[{}\begin{matrix}x>1\\x< -5\end{matrix}\right.\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}1< x< \dfrac{7}{2}\\x< -5\end{matrix}\right.\)

Vậy \(\left[{}\begin{matrix}x>1\\x< -5\end{matrix}\right.\)

Answer 2

[Anh Lan]

cảm ơn bạn nhiều nha