Question

[Nguyễn Mai Linh Đan]

G giúp mình mới mình cần gấp

Answer 1

[『Kuroba ム Tsuki Ryoo ︵²ᵏ⁷』]

`#3107.101107`

`j)`

\(1\dfrac{3}{4}-x=\dfrac{-3}{16}+\dfrac{7}{16}\\ \Rightarrow1\dfrac{3}{4}-x=\dfrac{4}{16}\\ \Rightarrow1\dfrac{3}{4}-x=\dfrac{1}{4}\\ \Rightarrow x=1\dfrac{3}{4}-\dfrac{1}{4}\\ \Rightarrow x=\dfrac{3}{2}\)

Vậy, `x =`\(\dfrac{3}{2}.\)

Answer 2

[Nguyễn Lê Phước Thịnh]

\(1\dfrac{3}{4}-x=\dfrac{-3}{16}+\dfrac{7}{16}\)

=>\(\dfrac{7}{4}-x=\dfrac{1}{4}\)

=>\(x=\dfrac{7}{4}-\dfrac{1}{4}=\dfrac{6}{4}=\dfrac{3}{2}\)