Question

[Dương Tinh Tú]

\(\frac{x-3}{3xy}\)+ \(\frac{5x+3}{3xy}\)

\(\frac{5x-7}{2x-3}+\frac{4-3x}{2x-3}\)

\(\frac{3x+5}{7x-1}-\frac{6-4x}{7x-1}\)

\(\frac{11x-7}{3-5x}-\frac{6x+4}{5x-3}\)

\(\frac{3}{2x+6}-\frac{x-6}{2x^2+6x}\)

\(\frac{1}{2x-10}+\frac{2x}{3x^2-15x}\)

Answer 1

[Rotten Girl]

1/ \(\frac{x-3}{3xy}\)+\(\frac{5x+3}{3xy}\)= \(\frac{6x}{3xy}\)=\(\frac{3}{y}\)

2/\(\frac{5x-7}{2x-3}\)+\(\frac{4-3x}{2x-3}\)=\(\frac{2x-3}{2x-3}\)=1

3/\(\frac{11x-7}{3-5x}\)-\(\frac{6x+4}{5x-3}\)=\(\frac{11x-7}{3-5x}\)+\(\frac{6x+4}{3-5x}\)=\(\frac{17x-3}{3-5x}\)

4/\(\frac{3}{2x+6}\)-\(\frac{x-6}{2x^2+6x}\)=\(\frac{3x}{x\left(2x+6\right)}\)-\(\frac{x-6}{x\left(2x+6\right)}\)=\(\frac{2x-6}{x\left(2x+6\right)}\)

5/\(\frac{1}{2x-10}\)+\(\frac{2x}{3x^2-15x}\)=\(\frac{1}{2\left(x-5\right)}\)+\(\frac{2x}{3x\left(x-5\right)}\)=\(\frac{3x}{6x \left(x-5\right)}\)+\(\frac{4x}{6x\left(x-5\right)}\)

=\(\frac{7x}{6x\left(x-5\right)}\)=\(\frac{7}{6\left(x-5\right)}\)