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M = \(\frac{1}{3}\)+ \(\frac{1}{6}\)+ \(\frac{1}{10}\)+ \(\frac{1}{15}\)( Mẫu chung: 60 )
M = \(\frac{20}{60}\)+ \(\frac{10}{60}\)+ \(\frac{6}{60}\)+ \(\frac{4}{60}\)
M = \(\frac{40}{60}\)
M = \(\frac{2}{3}\)
M=\(\frac{1}{3}\)+\(\frac{1}{6}\)+\(\frac{1}{10}\)+\(\frac{1}{15}\)=\(\frac{1}{3}\)(1+\(\frac{1}{2}\)+\(\frac{1}{5}\))+\(\frac{1}{10}\)=\(\frac{1}{3}\)*\(\frac{17}{10}\)+\(\frac{3}{30}\)=\(\frac{20}{30}\)=\(\frac{2}{3}\)
\(M=\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+\frac{1}{1+2+3+4+5}\)
\(M=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}\)
\(M=\frac{2}{3}\)
\(M=\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+\frac{1}{1+2+3+4+5}\)
\(M=\frac{1}{\left(1+2\right).2:2}+\frac{1}{\left(1+3\right).3:2}+\frac{1}{\left(1+4\right).4:2}+\frac{1}{\left(1+5\right).5:2}\)
\(M=\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+\frac{2}{5.6}\)
\(M=2.\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}\right)\)
\(M=2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\right)\)
\(M=2.\left(\frac{1}{2}-\frac{1}{6}\right)\)
\(M=2.\frac{1}{2}-2.\frac{1}{6}\)
\(M=1-\frac{1}{3}=\frac{2}{3}\)
\(\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4+5}\) = \(\frac{1}{3}+\frac{1}{6}+\frac{1}{15}\)= \(\frac{10}{30}+\frac{5}{30}+\frac{2}{30}\)= \(\frac{10+5+2}{30}\)= \(\frac{17}{30}\)
Trong đề có 4 đáp án là a)\(\frac{1}{6}\)
b)\(\frac{5}{6}\)
c) \(\frac{1}{3}\)
d)\(\frac{2}{3}\)
Chu vi của hình tam giác đó là :
\(3\frac{1}{2}+5\frac{2}{3}+7\frac{1}{6}=16\frac{1}{3}\left(m\right)\)
Đáp số : ...........
~~Học tốt~~
\(\frac{1}{3}m^2+\frac{1}{3}m^2+1\frac{1}{3}m^2=\frac{2}{3}m^2+\frac{4}{3}m^2=\frac{6}{3}m^2=2m^2\)
1/3m2+1/3m2+4/3m2=2m2