Câu hỏi của Uyên Nhi

Question

f)$\dfrac{x^2-6x+9}{x^2-8x+15}=$l)$\dfrac{5yx+5x+3+3y}{10xy-15x-9-6y}=$

Gia Linh · Accepted Answer

$f,\dfrac{x^2-6x+9}{x^2-8x+15}\
=\dfrac{\left(x-3\right)^2}{\left(x-3\right)\left(x-5\right)}\
=\dfrac{x-3}{x-5}\
l,\dfrac{5xy+5x+3+3y}{10xy-15x-9+6y}\
=\dfrac{5x\left(y+1\right)+3\left(y+1\right)}{5x\left(2y-3\right)+3\left(2y-3\right)}\
=\dfrac{\left(y+1\right)\left(5x+3\right)}{\left(2y-3\right)\left(5y+3\right)}\
=\dfrac{y+1}{2y-3}$Câu trả lời: $f,\dfrac{x^2-6x+9}{x^2-8x+15}\
=\dfrac{\left(x-3\right)^2}{\left(x-3\right)\left(x-5\right)}\
=\dfrac{x-3}{x-5}\
l,\dfrac{5xy+5x+3+3y}{10xy-15x-9+6y}\
=\dfrac{5x\left(y+1\right)+3\left(y+1\right)}{5x\left(2y-3\right)+3\left(2y-3\right)}\
=\dfrac{\left(y+1\right)\left(5x+3\right)}{\left(2y-3\right)\left(5y+3\right)}\
=\dfrac{y+1}{2y-3}$

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