Question

[๖ACEn4m⁀ᶦᵈᵒᶫ]

e, x²-4+(x-2)²  = 0   

f, x³+1=x(x+1)

g, x²(x-3)+12-4x = 0   

h, (2x-1)²-(x+3)² = 0

Answer 1

[GV Nguyễn Trần Thành Đạt]

Đề bài yêu cầu giải pt?

Answer 2

[Nguyễn Huy Tú]

e, \(\left(x-2\right)\left(x+2\right)+\left(x-2\right)^2=0\Leftrightarrow\left(x-2\right)\left(x+2+x-2\right)=0\Leftrightarrow x=0;x=2\)

f, \(\left(x+1\right)\left(x^2-x+1\right)-x\left(x+1\right)=0\Leftrightarrow\left(x+1\right)\left(x-1\right)^2=0\Leftrightarrow x=1;x=-1\)

g, \(x^2\left(x-3\right)+4\left(3-x\right)=0\Leftrightarrow\left(x-2\right)\left(x+2\right)\left(x-3\right)=0\Leftrightarrow x=2;x=-2;x=3\)

h, \(\left(2x-1-x-3\right)\left(2x-1+x+3\right)=0\Leftrightarrow\left(x-4\right)\left(3x+2\right)=0\Leftrightarrow x=4;x=-\dfrac{2}{3}\)