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a/ \(ab-2b-3a+6=\left(ab-2b\right)-\left(3a-6\right)=b\left(a-2\right)-3\left(a-2\right)=\left(a-2\right)\left(b-3\right)\)
b/ \(ax-by-ay+bx==\left(ax+bx\right)-\left(by+ay\right)=x\left(a+b\right)-y\left(b+a\right)=\left(a+b\right)\left(x-y\right)\)
c/ \(ax+by-ay-bx=\left(ax-ay\right)+\left(by-bx\right)=a\left(x-y\right)+b\left(y-x\right)=a\left(x-y\right)-b\left(x-y\right)=\left(x-y\right)\left(a-b\right)\)
d/ \(a^2-\left(b+c\right)a+bc=a^2-ab-ac+bc=\left(a^2-ac\right)+\left(ab-bc\right)=a\left(a-c\right)+b\left(a-c\right)=\left(a-c\right)\left(a+b\right)\)e/ \(\left(3a-2\right)\left(4a-3\right)-\left(2-3a\right)\left(3a+1\right)=\left(3a-2\right)\left(4a-3\right)+\left(3a-2\right)\left(3a+1\right)=\left(3a-2\right)\left(4a-3+3a+1\right)=\left(3a-2\right)\left(7a-2\right)\)
f/ \(ax+ay+az-bx-by-bz-x-y-z=\left(ax+ay+az\right)-\left(bx+by+bz\right)-\left(x+y+z\right)\)
\(=a\left(x+y+z\right)-b\left(x+y+z\right)-\left(x+y+z\right)=\left(x+y+z\right)\left(a-b-1\right)\)
A) ax-bx+x+ay-by+y
=x.(a-b+1)+y.(a-b+1)
=(a-b+1)(x+y)
B) am+an+ap-bm-bn-bp-m-n-p
=a.(m+n+p)-b.(m+n+p)-(m+n+p)
=(m+n+p)(a-b-1)
a) ax-bx+x+ay-by+y
= (a-b+1)x+(a-b+1)y
= (a-b+1)(x+y)
b) am+an+ap-bm-bn-bp-m-n-p
= a(m+n+p)-b(m+n+p)-(m+n+p)
= (a-b-1)(m+n+p)
a/ \(x\left(a+b\right)+y\left(a+b\right)=\left(x+y\right)\left(a+b\right)\)
b/ \(a\left(x+y\right)+b\left(x+y\right)-1\left(x+y\right)=\left(a+b-1\right)\left(x+y\right)\)
c/ \(=x^2z\left(x+y-z-yz\right)\)
Ta có :
A= ax+ay+bx+by+x+y
= a(x+y)+b(x+y)+x+y
= (a+b+1)(x+y)
= (\(\dfrac{1}{3}\)+1).\(\dfrac{-9}{4}\)
= \(\dfrac{4}{3}.\dfrac{-9}{4}\)
= -3
B= ax+ay-bx-by-x-y
= a(x+y)-b(x+y)-(x+y)
= (a-b-1)(x+y)
= (\(\dfrac{1}{2}\)-1).\(\dfrac{1}{2}\)
= \(\dfrac{-1}{2}.\dfrac{1}{2}\)
= \(\dfrac{-1}{4}\)
a)\(ax-by+bx-ay\)
\(=\left(ax-ay\right)+\left(bx-by\right)\)
\(=a\left(x-y\right)+b\left(x-y\right)\)
\(=\left(a+b\right)\left(x-y\right)\)
b) sai đề
AX -BY - AY + BX = AX - AY + BX - BY = A . ( X - Y ) + B . ( X - Y ) = ( A + B ) . ( X - Y ) còn 2 câu còn lại bạn tự làm nhé , mình bận đi học rồi , nếu trưa mà vẫn ko có ai trả lời thì hỏi mình nha