Question

[hoàng trần]

Cộng trừ phân thức
(1)/(x^(2)-x+1)+1-(x^(2)+2)/(x^(3)+1)

Answer 1

[Kenny]

\(\dfrac{1}{x^2-x+1}-\dfrac{x^2+2}{x^3+1}=\dfrac{1}{x^2-x+1}-\dfrac{x^2+2}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{x+1}{\left(x+1\right)\left(x^2-x+1\right)}-\dfrac{x^2+2}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{x+1-x^2-2}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{-x^2+x-1}{\left(x+1\right)\left(x^2-x+1\right)}\)

Answer 2

[hoàng trần]

cảm ơn :))