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\(2\frac{1}{3}=\frac{7}{3};4\frac{2}{5}=\frac{22}{5};3\frac{1}{4}=\frac{13}{4};9\frac{5}{7}=\frac{68}{7};10\frac{3}{10}=\frac{103}{10}\)
\(2\frac{3}{5}=\frac{2x5+3}{5}=\frac{10+3}{5}=\frac{13}{5}\)
\(5\frac{4}{9}=\frac{5x9+4}{9}=\frac{45+4}{9}=\frac{49}{9}\)
\(9\frac{3}{8}=\frac{9x8+3}{8}=\frac{72+3}{8}=\frac{75}{8}\)
\(12\frac{7}{10}=\frac{12x10+7}{10}=\frac{120+7}{10}=\frac{127}{10}\)
\(2\frac{3}{5}=\frac{13}{5}\)
\(5\frac{4}{9}=\frac{49}{9}\)
\(9\frac{3}{8}=\frac{75}{8}\)
\(12\frac{7}{10}=\frac{127}{10}\)
\(3\frac{2}{5}=\frac{3\cdot5+2}{5}=\frac{17}{5}\)
\(2\frac{1}{7}=\frac{2\cdot7+1}{7}=\frac{15}{7}\)
\(8\frac{1}{6}=\frac{8\cdot6+1}{6}=\frac{49}{6}\)
\(2\frac{1}{2}=\frac{2\cdot2+1}{2}=\frac{5}{2}\)
\(3\frac{2}{5}\cdot2\frac{1}{7}=\frac{17}{5}\cdot\frac{15}{7}=\frac{51}{7}\)
\(8\frac{1}{6}:2\frac{1}{2}=\frac{49}{6}:\frac{5}{2}=\frac{49}{6}\cdot\frac{2}{5}=\frac{49}{15}\)
3/2+5/3
=19/6
8/3-11/7
=23/21
8/3*21/4
=168/12=14
7/2:9/4
=7/2*4/9
=28/18=10//9
\(1\frac{1}{2}+1\frac{1}{3}=\frac{3}{2}+\frac{4}{3}=\frac{9}{6}+\frac{8}{6}=\frac{17}{6}\)
\(2\frac{2}{3}-1\frac{4}{7}=\frac{8}{3}-\frac{11}{7}=\frac{56}{21}-\frac{33}{21}=\frac{23}{21}\)
\(2\frac{2}{3}\cdot5\frac{1}{4}=\frac{8}{3}.\frac{21}{4}=14\)
\(3\frac{1}{2}:2\frac{1}{4}=\frac{7}{2}:\frac{9}{4}=\frac{7}{2}.\frac{4}{9}=\frac{14}{9}\)
65/7+38/7=103/7
103/10-47/10=56/10
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