Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Tử số=1/2+2/3+3/4+...........+99/100
=1-1/2+1-1/3+1-1/4+...........+1-1/100
=1.100-(1/2+1/3+1/4+............+1/100)
=100-(1/2+1/3+1/4+............+1/100)
=Mẫu số
=>Phép tính trên có giá trị bằng 1.
\(\Rightarrow C=\frac{1}{100}-\left(\frac{1}{100\cdot99}+\frac{1}{99\cdot98}+\frac{1}{98\cdot97}+...+\frac{1}{3\cdot2}+\frac{1}{2\cdot1}\right)\)
\(\Rightarrow C=\frac{1}{100}-\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+...+\frac{1}{98\cdot99}+\frac{1}{99\cdot100}\right)\)
\(\Rightarrow C=\frac{1}{100}-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\right)\)
\(\Rightarrow C=\frac{1}{100}-\left(1-\frac{1}{100}\right)\)
\(\Rightarrow C=\frac{1}{100}-1+\frac{1}{100}\)
\(\Rightarrow C=\left(\frac{1}{100}+\frac{1}{100}\right)-1\)
\(\Rightarrow C=\frac{1}{50}-1\)
\(\Rightarrow C=\frac{-49}{50}\)
\(\frac{B}{2}=\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+...+\frac{1}{2^{99}}+\frac{1}{2^{100}}\)
\(\frac{B}{2}=B-\frac{B}{2}=\frac{1}{2}-\frac{1}{2^{100}}< 1\)
(101+100+99+98+...+3+2+1)/(101-100+99-98+...+3-2+1)
=101+100+99+98+...+3+2+1
=101 . (101 + 2) : 2
=5151
101-100+99-98+...+3-2+1
=(101-100)+(99-98)+...+(3-2)+1
=1 + 1 + 1 + ... + 1
=101- 2 + 1
=100 : 2
=50 + 1
=51
(101 + 100 + 99 + 98 + ... + 3+2+1) / (101-100+99-98+...+3-2+1) = 5151/51 = 101
\(\frac{1}{2!}+\frac{2}{3!}+...+\frac{99}{100!}\)
\(=\frac{2-1}{2!}+\frac{3-1}{3!}+...+\frac{100-1}{100!}\)
\(=\frac{2}{2!}-\frac{1}{2!}+\frac{3}{3!}-\frac{1}{3!}+...+\frac{100}{100!}-\frac{1}{100!}\)
\(=1-\frac{1}{2!}+\frac{1}{2!}-\frac{1}{3!}+...+\frac{1}{99!}-\frac{1}{100!}\)
\(=1-\frac{1}{100!}< 1\)