Câu hỏi của Nguyễn Thị Thu Hiền

Question

cho $\sin\alpha=\frac{3}{5}$. Tinh $\cot\alpha$,$\tan\alpha$, $\cos\alpha$

Ami Mizuno · Accepted Answer

Có: cos$\alpha=\sqrt{1-sin^2\alpha}$=$\sqrt{1-\left(\frac{3}{5}\right)^2}=\frac{4}{5}$

tan$\alpha=\frac{sin\alpha}{cos\alpha}=\frac{3.5}{5.4}=\frac{3}{4}$

cot$\alpha=\frac{1}{tan\alpha}$$=\frac{4}{3}$Câu trả lời: Có: cos$\alpha=\sqrt{1-sin^2\alpha}$=$\sqrt{1-\left(\frac{3}{5}\right)^2}=\frac{4}{5}$

tan$\alpha=\frac{sin\alpha}{cos\alpha}=\frac{3.5}{5.4}=\frac{3}{4}$

cot$\alpha=\frac{1}{tan\alpha}$$=\frac{4}{3}$