Question

[Phạm Vĩnh Linh]

Cho c²==ab . Chứng minh rằng :

a) \(\dfrac{a^{2^{ }}+c^2}{b^{2^{ }}+c^{2^{ }}}=\dfrac{a}{b}\)

b)\(\dfrac{b^{2^{ }}-a^{2^{ }}}{a^{2^{ }}+c^2}=\dfrac{b-a}{a}\)

Answer 1

[Trần Mạnh]

a/ \(\dfrac{a^2+c^2}{b^2+c^2}=\dfrac{a}{b}\)

\(Tacó\dfrac{a^2+ab}{b^2+ab}=\dfrac{a\left(a+b\right)}{b\left(b+a\right)}=\dfrac{a}{b}\) (vì \(c^2=ab\) )

Vậy....