Question

[Line Shinto]

Cho a+b+c =2015 and \(\frac{1}{a+b}+\frac{1}{b+c}+\frac{1}{a+c}=\frac{1}{10}\)

Tính \(S=\frac{c}{a+b}+\frac{a}{b+c}+\frac{b}{c+a}\)

Answer 1

[Trần Thị Loan]

\(S=\frac{2015-\left(a+b\right)}{a+b}+\frac{2015-\left(b+c\right)}{b+c}+\frac{2015-\left(a+c\right)}{a+c}=\frac{2015}{a+b}-\frac{a+b}{a+b}+\frac{2015}{b+c}-\frac{b+c}{b+c}+\frac{2015}{a+c}-\frac{a+c}{a+c}\)

\(S=2015.\left(\frac{1}{a+b}+\frac{1}{b+c}+\frac{1}{a+c}\right)-3=2015.\frac{1}{10}-3=\frac{1085}{10}\)