Question

[Phú Phạm Minh]

Cho a,b,c > 0. CMR: \(\dfrac{a^2}{b}+\dfrac{b^2}{c}+\dfrac{c^2}{a}\ge a+b+c\).

Answer 1

[Phạm Minh Quang]

Ta có: \(\dfrac{a^2}{b}+\dfrac{b^2}{c}+\dfrac{c^2}{a}\ge\dfrac{\left(a+b+c\right)^2}{a+b+c}=a+b+c\)

Dấu "=" xảy ra \(\Leftrightarrow a=b=c\)