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5 tháng 9 2016

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5 tháng 9 2016

Ta có 

(m+n+p)^q >= m^q+n^q+p^q

=>a+b+c=1

=>(a+b+c)^2016=1 >= a2016 + b2016 + c2016

Mà  a2016 + b2016 + c2016 >=0

=>  a2016 + b2016 + c2016=1

13 tháng 9 2021

\(201^2=\left(200+1\right)^2=200^2+2.200.1+1^2=40000+400+1=40401\)

\(498^2=\left(500-2\right)^2=500^2-2.500.2+2^2=250000-2000+4=248004\)

 

 

 

13 tháng 9 2021

\(93.107=\left(100-7\right)\left(100+7\right)=100^2-7^2=10000-49=9951\)

\(2016^2-2015.2017=2016^2-\left(2016-1\right)\left(2016+1\right)=2016^2-2016^2+1^2=1\)

1 tháng 7 2017

a2+b2+c2=ab+bc+ca

<=>2a2+2b2+2c2=2ab+2bc+2ca

<=>(a2-2ab+b2)+(b2-2bc+c2)+(c2-2ca+a2)=0

<=>(a-b)2+(b-c)2+(c-a)2=0

<=>a=b=c

mà a+b+c=3<=>a=b=c=1

=>P=0

20 tháng 9 2018

P=2017 chứ bạn