Question

[tran ha phuong]

Cho A = \(\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+....+\frac{1}{9^2}.\)Chứng minh \(\frac{2}{5}\)< A < \(\frac{8}{9}\)

Answer 1

[LeThiHaiAnh✔]

\(A< \frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{8.9}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{8}-\frac{1}{9}=1-\frac{1}{9}=\frac{8}{9}\)

\(A>\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}=\frac{1}{2}-\frac{1}{10}=\frac{2}{5}\)

\(\Rightarrow\frac{2}{5}< A< \frac{8}{8}\)

Vây:.....

- Hok tốt ~

Answer 2

[LeThiHaiAnh✔]

- k bn ơi ~