Question

[Hiền Nguyễn Thị]

Cho a, b, c là ba cạnh tam giác, gọi p là nửa chu vi. CMR:

\(2p\le\frac{ab}{c}+\frac{bc}{a}+\frac{ca}{b}\)

Answer 1

[Phùng Minh Quân]

\(\hept{\begin{cases}\frac{ab}{c}+\frac{bc}{a}\ge2b\\\frac{bc}{a}+\frac{ca}{b}\ge2c\\\frac{ca}{b}+\frac{ab}{c}\ge2a\end{cases}}\) :)))