Question

[Park Ji Yeon]

c=\(\frac{16}{15\cdot31}+\frac{14}{31\cdot45}+\frac{7}{45\cdot52}+\frac{7}{52\cdot65}+\frac{1}{13\cdot70}\)

Answer 1

[KAl(SO4)2·12H2O]

\(C=\frac{16}{15.31}+\frac{14}{31.45}+\frac{7}{45.52}+\frac{7}{52.65}+\frac{1}{13.70}\)

\(C=\frac{16}{15.31}+\frac{14}{31.45}+\frac{7}{45.52}+\frac{13}{52.65}+\frac{5}{67.70}\)

\(C=\frac{1}{15}-\frac{1}{31}+\frac{1}{31}-\frac{1}{45}+\frac{1}{45}-\frac{1}{52}+\frac{1}{52}-\frac{1}{65}+\frac{1}{65}-\frac{1}{70}\)

\(C=\frac{1}{15}-\frac{1}{70}\)

\(C=\frac{11}{210}\)

Vậy: \(C=\frac{11}{210}\)

Answer 2

[Pikachu]

C \(=\frac{898}{17745}\)

Tk mk nhé