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`3/7+2/5+4/7`
`=(3/7+4/7)+2/5`
`=1+2/5`
`=5/5+2/5`
`=7/5`
`20/34+4/9+7/17`
`=(20/34+7/17)+4/9`
`=(20/34+14/34)+4/9`
`=34/34+4/9`
`=1+4/9`
`=9/9+4/9`
`=13/9`
`48xx2+96+48xx6`
`=48xx2+48xx2+48xx6`
`=48xx(2+2+6)`
`=48xx10`
`=480`
câu thứ hai thì làm như này em nhé:
\(\dfrac{20}{34}\) + \(\dfrac{4}{9}\) + \(\dfrac{7}{17}\)
= (\(\dfrac{20}{34}\) + \(\dfrac{7}{17}\)) + \(\dfrac{4}{9}\)
= (\(\dfrac{10}{17}\) + \(\dfrac{7}{17}\)) + \(\dfrac{4}{9}\)
= 1 + \(\dfrac{4}{9}\)
= \(\dfrac{13}{9}\)
`2/5 xx 4/7 + 3/5 xx 4/7`
`= 4/7 xx (2/5 + 3/5)`
`= 4/7 xx 1`
`= 4/7`
\(=\dfrac{2}{5}\cdot\dfrac{7}{3}\cdot\dfrac{3}{7}\cdot\dfrac{5}{2}+2020=1+2020=2021\)
5/7 - 2/5 x 4/6
= 5/7 - 2/5 x 2/3
= 5/2 x 2/7 - 2/5 x 2/3
= 5/2 x 2/7 + 5/2 x 2/3
= 5/2 x 4/21
= 10/21
5/7 - 2/5 x4/6
= 5/7 - 8/30
= 5/7 - 4/15
= (75- 28)/ 105
= 47/105
a) \(19\times\left(52+38\right)-9\times\left(52+38\right)=\)
\(=\) \(19\times90-9\times90\)
\(=90\times\left(19-9\right)\)
\(=90\times10\)
\(=900\)
b) \(\dfrac{2}{5}\div\dfrac{3}{7}\times\dfrac{3}{7}\div\dfrac{2}{5}+2019=\)
\(=\left(\dfrac{2}{5}\div\dfrac{2}{5}\right)\times\left(\dfrac{3}{7}\div\dfrac{3}{7}\right)+2019\)
\(=1\times1+2019\)
\(=2019\)
\(2\times3\times5\times7\)
\(=\left(2\times5\right)\times\left(3\times7\right)\)
\(=10\times21\)
\(=210\)
Ta có:
\(\frac{2}{5}\text{x}51+\frac{2}{5}+\frac{2}{5}\text{x}48\)
\(=\frac{2}{5}\text{x}51+\frac{2}{5}\text{x}1+\frac{2}{5}\text{x}48\)
\(=\frac{2}{5}\left(51+1+48\right)\)
\(=\frac{2}{5}\text{x}100\)
\(=0,4\text{x}100\)
\(=40\)