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a) 210:[16+3.(6+3.2^2)]-3
=210:[16+3.(6+3.4)]-3
=210:[16+3.(6+12)]-3
=210:[16+3.18]-3
=210:[16+54]-3
=210:70-3
=3-3
=0
\(500-\left\{5.\left[409.\left(2^3.3-21\right)^2\right]\right\}-3\)
\(\left\{210:\left[16+3\cdot\left(6+3\cdot2^2\right)\right]\right\}\)
\(=210:\left[16+3\cdot\left(6+3\cdot4\right)\right]\)
\(=210:\left[16+3\cdot\left(6+12\right)\right]\)
\(=210:\left(16+3\cdot18\right)\)
\(=210:\left(16+54\right)\)
\(=210:70\)
\(=3\)
#Urushi
\(\left\{210:\left[16+3.\left(6+3.2^2\right)\right]\right\}-3\)
\(=\left\{210:\left[16+3.\left(6+12\right)\right]\right\}-3\)
\(=\left\{210:\left[16+3.18\right]\right\}-3\)
\(=\left\{210:\left[16+54\right]\right\}-3\)
\(=\left\{210:70\right\}-3=3-3=0\)
36 . 46 = (3.4)6 = 126
82 . 23 . 162 = (23)2 . 23 . (24)
= 26 . 23 . 24 = 26 + 3 + 4 = 213
23 . 22 . 83 = 23 . 22 . (23)3
= 23 . 22 . 29 = 23 + 2 + 9 = 214
y. y7 = y1 + 7 = y8
\(3^6\cdot4^6=\left(3\cdot4\right)^6=12^6\)
\(8^2\cdot2^3\cdot16^2=\left(2^3\right)^2\cdot2^3\cdot\left(2^4\right)^2\)
\(=2^6\cdot2^3\cdot2^8=2^{17}\)
\(2^3\cdot2^2\cdot8^3=2^5\cdot\left(2^3\right)^3\)
\(2^5\cdot2^9=2^{14}\)
\(y\cdot y^7=y^{1+7}=y^8\)
\(\left\{210:\left[16+3.\left(6+3.22\right)\right]\right\}-3\)
\(=\left\{210:\left[16+3.\left(6+66\right)\right]\right\}-3\)
\(=\left\{210:\left[16+3.72\right]\right\}-3\)
\(=\left\{210:\left[16+216\right]\right\}-3\)
\(=\left\{210:232\right\}-3\)
\(=\dfrac{105}{116}-3\)
\(=\dfrac{-243}{116}\)
nhóm cứ hai số liên tiếp lại vs nhâu sẽ đk quy luật tổng của toàn số -2
A=2-4+6-8+10-12+14-16+18-20+22-24+26-28+30-32
A= (-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)+(-2)
A= -16
a) \(2^5+5.13-3.2^3\)
\(=32+5.13-3.8\)
\(=32+65-24\)
\(=97-24\)
\(=73\)
b) \(5^{13}:5^{10}-5^2.2^2\)
\(=5^3-25.4\)
\(=125-100\)
\(=25\)
c) \(4^5:4^3-3^9:3^7+5^0\)
\(=4^2-3^2+1\)
\(=16-9+1\)
\(=7+1\)
\(=8\)
{210:[16+3.(6+3.2^2)]}-3
={210:[16+3.(6+3.4)]}-3
={210:[16+3.(6+12)]}-3
={210:[16+3.18)]}-3
={210:[16+54)]}-3
={210:70)]}-3
=30-3
=27
=27 nhớ tít