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Tính các tổng sau:
1, S=1-2+3_4+..+25-26
S =-1+3-5+7-...-53+55 ( có 28 số hạng )
= (-1+3)+(-5+7)+...+(-53+55) ( có 28:2=14 nhóm )
= 2+2+...+2
= 2 . 14
= 28
`@` `\text {Ans}`
`\downarrow`
`a)`
\(\dfrac{1}{2}-\dfrac{5}{6}+\dfrac{11}{33}-\dfrac{35}{40}\)
`=`\(\dfrac{1}{2}-\dfrac{5}{6}+\dfrac{1}{3}-\dfrac{7}{8}\)
`=`\(\dfrac{12}{24}-\dfrac{20}{24}+\dfrac{8}{24}-\dfrac{21}{24}\)
`= -21/24 = -7/8`
`b)`
\(\dfrac{2}{3}\cdot1\dfrac{3}{4}-\dfrac{8}{9}-\dfrac{17}{51}-\dfrac{1}{5}\)
`=`\(\dfrac{2}{3}\cdot\dfrac{7}{4}-\dfrac{8}{9}-\dfrac{17}{51}-\dfrac{1}{5}\)
`=`\(\dfrac{7}{6}-\dfrac{8}{9}-\dfrac{17}{51}-\dfrac{1}{5}\)
`=`\(\dfrac{5}{18}-\dfrac{17}{51}-\dfrac{1}{5}\)
`=`\(-\dfrac{1}{18}-\dfrac{1}{5}=-\dfrac{23}{90}\)
`c)`
\(\dfrac{1}{2}\cdot2-2\dfrac{5}{7}+\dfrac{6}{4}-\dfrac{10}{15}\)
`=`\(1-\dfrac{19}{7}+\dfrac{6}{4}-\dfrac{10}{15}\)
`=`\(-\dfrac{12}{7}+\dfrac{6}{4}-\dfrac{10}{15}\)
`=`\(-\dfrac{3}{14}-\dfrac{10}{15}=-\dfrac{37}{42}\)
`d) `
\(\dfrac{1}{6}\cdot\dfrac{1}{11}+\dfrac{4}{11}\cdot\left(-\dfrac{1}{6}\right)+\dfrac{8}{11}\cdot\dfrac{1}{6}+\dfrac{1}{6}\cdot\dfrac{6}{11}\)
`=`\(\dfrac{1}{6}\cdot\left(\dfrac{1}{11}-\dfrac{4}{11}+\dfrac{8}{11}+\dfrac{6}{11}\right)\)
`=`\(\dfrac{1}{6}\cdot\left(\dfrac{1-4+8+6}{11}\right)\)
`=`\(\dfrac{1}{6}\cdot1=\dfrac{1}{6}\)
`e)`
\(-17\cdot\left(-23\right)+\left(-53\right)\cdot17+17\cdot14+17\cdot\left(-24\right)\)
`= 17*(23-53+14-24)`
`= 17*(-40)`
`= -680`
`f)`
\(-19\cdot218+\left(-82\right)\cdot19-533\cdot19+\left(-19\right)\cdot167\)
`= 19*(-218-82-533-167)`
`= 19*(-1000)`
`= -19000`
`g)`
\(\dfrac{2}{5}+\dfrac{3}{8}-\dfrac{11}{44}+\dfrac{9}{16}\)
`=`\(\dfrac{2}{5}+\dfrac{3}{8}-\dfrac{1}{4}+\dfrac{9}{16}\)
`=`\(\dfrac{31}{40}-\dfrac{1}{4}+\dfrac{9}{16}\)
`=`\(\dfrac{21}{40}+\dfrac{9}{16}=\dfrac{87}{80}\)
`h)`
\(\dfrac{4}{10}-1\dfrac{5}{6}\cdot2+\dfrac{7}{8}-\dfrac{1}{9}\)
`=`\(\dfrac{4}{10}-\dfrac{11}{6}\cdot2+\dfrac{7}{8}-\dfrac{1}{9}\)
`=`\(\dfrac{4}{10}-\dfrac{11}{3}+\dfrac{7}{8}-\dfrac{1}{9}\)
`=`\(-\dfrac{49}{15}+\dfrac{7}{8}-\dfrac{1}{9}\)
`=`\(-\dfrac{287}{120}-\dfrac{1}{9}=-\dfrac{901}{360}\)
`i )`
\(3\cdot\dfrac{1}{5}-\dfrac{2}{8}-\dfrac{12}{36}+\dfrac{15}{9}\)
`=`\(\dfrac{3}{5}-\dfrac{1}{4}-\dfrac{1}{3}+\dfrac{15}{9}\)
`=`\(\dfrac{7}{20}-\dfrac{1}{3}+\dfrac{15}{9}\)
`=`\(\dfrac{1}{60}+\dfrac{15}{9}=-\dfrac{33}{20}\)
`k)`
\(\dfrac{6}{8}\cdot3\dfrac{1}{2}+4\dfrac{2}{3}-\dfrac{11}{55}+\dfrac{17}{51}\)
`=`\(\dfrac{3}{4}\cdot\dfrac{7}{2}+\dfrac{14}{3}-\dfrac{1}{5}+\dfrac{17}{51}\)
`=`\(\dfrac{21}{8}+\dfrac{14}{3}-\dfrac{1}{5}+\dfrac{17}{51}\)
`=`\(\dfrac{175}{24}-\dfrac{1}{5}+\dfrac{17}{51}\)
`=`\(\dfrac{851}{120}+\dfrac{17}{51}=\dfrac{297}{40}\)
`l )`
\(\dfrac{1}{3}\cdot3\dfrac{1}{2}-4\dfrac{2}{5}-\dfrac{26}{78}+\dfrac{17}{51}\)
`=`\(\dfrac{1}{3}\cdot\dfrac{7}{2}-\dfrac{22}{5}-\dfrac{1}{3}+\dfrac{17}{51}\)
`=`\(\dfrac{1}{3}\left(\dfrac{7}{2}-1\right)-\dfrac{22}{5}+\dfrac{17}{51}\)
`=`\(\dfrac{1}{3}\cdot\dfrac{5}{2}-\dfrac{22}{5}+\dfrac{17}{51}\)
`=`\(\dfrac{5}{6}-\dfrac{22}{5}+\dfrac{17}{51}\)
`=`\(-\dfrac{107}{30}+\dfrac{17}{51}=-\dfrac{97}{30}\)
P/s: Bạn tách bài ra hỏi nhé! Và ghi đề rõ ràng chứ đừng ghi ntnay, nhiều bạn nhìn vào rất khó nhìn!
`# \text {KaizulvG}`
80 - 4 . 52 + 3 .23=80 - 4 . 25 + 3 . 8=80 - 100 +24=-20+24=4
25 . 124 - 24 . 25 +212=24 .(124 - 25)+212=24 . 99 +212=2376 +212=2588
35 . 48 + 65 . 68 + 20 . 35=35 . (48 +20)+65 . 68=35 . 68 +65 . 68=68 . (35 + 65)=68 . 100=6800
27 :23+23.20-110=24+23- 1=16 + 8 -1=23
câu 3,câu 6,câu 7 mk ko làm đc vì ko biết cách viết dấu móc vuông với dấu móc kép nha bạn.:) ^_^
HOK TỐT
a) 50 + 48 + 46 + ... + 4 - 47 - 45 - 43 - ... - 1
= (50 - 45) + (48 - 43) + (46 - 41) + ... + (6 - 1) + (4 - 47)
=72
Cứ gộp nhóm làm sao cho trong ngoặc đó bằng 5
b) 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + 10 - 11 - 12 + ... + 50 - 51 - 52 + 53 + 54
= (1 + 54) + (2 + 53) - (3 + 52) - (4 + 51) + ... + (25 + 30) + (26 + 29) - (27 + 28)
=55
Cứ gộp nhóm làm sao cho trong ngoặc đó bằng 55. Còn dấu đằng trước nhóm thì theo dấu đề bài cho
~ Học tốt ~
1/ 1 + (-2) + 3 + (-4) + . . . + 17 + (-18)
= [1 + (-2)] + [3 + (-4)] + . . . + [17 + (-18)]
= (-1) + (-1) + . . . + (-1)
18 : 2 = 9
= (-1) . 9
= -9
2/ -1 + 2 - 3 + 4 + . . . - 99 + 100
= (-1 + 2) + (-3 + 4) + . . . (-99 + 100)
= 1 + 1 + . . . + 1
100 : 2 = 50
= 1 . 50
= 50
3/ 2 – 4 + 6 – 8 + . . . + 48 – 50 + 51 - 52
= (2 – 4) + (6 – 8) + . . . + (46 - 48) + (– 50 + 51 - 52)
= (-2) + (-2) + . . . + (-2) + (-51)
(48 - 2) : 2 + 1 = 24 : 2 = 12
= (-2) . 12 + (-51)
= (-24) + (-51)
= -75
4/ – 1 + 3 – 5 + 7 - . . . . + 97 – 99 + 101
= (–1 + 3) + (–5 + 7) + . . . . + (-93 + 95) + (97 – 99 + 101)
= 2 + 2 + . . . . + 2 + 99
(95 - 1) : 2 + 1 = 48 : 2 = 24
= 2 . 24 + 99
= 48 + 99
= 147
5/ 1 + 2 – 3 – 4 + . . . . + 97 + 98
= (1 + 2 – 3 – 4) + . . . . + (93 + 94 - 95 - 96) + (97 + 98)
= (-4) + . . . . + (-4) + 195
96 : 4 = 24
= (-4) . 24 + 195
= -96 + 195
= 99
1/ 1 + (-2) + 3 + (-4) + . . . + 17 + (-18)
=(1+3+5+..+17)+[-2+(-3)+(-4)+..+(-18)
goi ben tong so duong la A va tong so am la B ta co
A co ssh la :(17-1):2+1=9
B co ssh la :[-18-(-2)]:2+1=9
=>A=(17+1).9:2=81
=>B=[-18+(-2)].9:2=-72
=> A+B= 81+(-72)=9
vay tong bang 9
\(1+2+3+...+n=\frac{n\left(n+1\right)}{2}\)
\(1+3+5+7+...+\left(2n-1\right)=n^2\)
\(2+4+6+8+...+2n=n\left(n+1\right)\)
Câu 1: 2/2.4 +2/4.6+2/6.8+.....+2/10.12
= 1/2-1/4+1/4-1/6+......+1/10-1/12
=1/2-1/12
=6/12-1/12
=5/12
Câu 2: =1-1/46
= 45/46
2/2.4 +2/4.6+2/6.8+.....+2/10.12
= 1/2-1/4+1/4-1/6+......+1/10-1/12
=1/2-1/12
=6/12-1/12
=5/12
Câu 2: =1-1/46
= 45/46