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Ỏ chỗ nếu gấp số thứ hai lên 2 lần thì trung bình cộng hai số là 24 hình như phải là trung bình cộng của 3 số đúng không bạn? Bạn kiểm tra lại giúp mk xem đề bài có đúng ko nhé!
Gọi 3 số cần tìm lần lượt là a, b, c
Có trung bình cộng của 3 số là 18 => \(\dfrac{a+b+c}{3}=18\)
=> a + b + c = 18x3 = 54 (1)
Nếu gấp số thứ nhất lên 2 lần thì trung bình cộng ba số là 22
=> \(\dfrac{2xa+b+c}{3}=22\)
=> 2xa + b + c = 22x3 = 66 (2)
Lấy (2) - (1), ta được:
(2xa + b + c) - (a + b + c) = 66 - 54 = 12
=> a = 12
Nếu gấp số thứ hai lên 2 lần thì trung bình cộng ba số là 24
=> \(\dfrac{a+2xb+c}{3}=24\)
=> a + 2xb + c = 24x3 = 72 (3)
Lấy (3) - (1), ta được
(a + 2xb + c) - (a + b + c) = 72 - 54 = 16
=> b = 18
Có a + b + c = 54, a = 12; b = 18
=> 12 + 18 + c = 54
=> c = 54 - 12 - 18 = 24
Vậy 3 số cần tìm lần lượt là 12; 18; 24
Chúc bạn học tốt!!!
Trung bình cộng của ba số trên là:
( 38 + 25 + 78 ) : 3 = 47
Đáp số : 47
TBC của 3 số đó là:
( 38+25+78 ) : 3=47
Đ/S: 47
tức là ( Số thứ nhất + Số thứ ba ) : 2 = Số thứ hai
=> Số thứ hai là 275
Chúc bạn hc tốt
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Bài 2:
Tổng của A, B, C là:
\(896\times3=2688\)
Tổng của A và C là:
\(860\times2=1720\)
Tổng của A và B là:
\(920\times2=1840\)
Số B là:
\(2688-1720=968\)
Số C là:
\(2688-1840=848\)
Số A là:
\(2688-968-848=872\)
Bài 3:
Tổng của 5 số là:
\(1672\times5=8360\)
Tổng của 4 số sau là:
\(1860\times4=7440\)
Số đầu là:
\(8360-7440=920\)
Tổng 5 số là:
162 x 5 = 810
Tổng số phần bằng nhau là:
2 + 1 + 3 = 6 phần
Số thứ 5 là:
810 : 6 x 2 = 270
Số thứ 4 là:
270 : 2 = 135
Đáp số : 270 và 135
Gọi số thứ nhất, hai , ba theo thứ tự đề bài là a, b và c.
Theo đề bài, ta có (a+b+c):3 = 126 ; a - b = 15 suy ra a = b+15 ; b - c =9 suy ra c = b - 9
Do đó \(\frac{a+b+c}{3}=126\Rightarrow b+15+b+b-9=378\Rightarrow3b=372\Rightarrow b=124\Rightarrow c=124-9=115\)
Vậy số thứ ba là 115
Trung bình cộng 3 số là:
(54+76+125):3=85
Đ/S: 75
_HT_
Trung bình cộng của 3 số là: ( 54+ 76 + 125 ) : 3 = 85