Question

[Phương Thảo Nguyễn]

Bài 1: Tính (hợp lý nếu có thể)                                        a) \(\left|-\frac{6}{7}\right|:\left(-2\right)^3-\sqrt{\frac{9}{16}}\)              b) \(-5\frac{5}{9}:\left(-1\frac{3}{4}\right)+4\frac{5}{9}:\left(-1\frac{3}{4}\right)\)       c) \(-63,99-\left(\frac{4}{9}-63,99\right)-\left(-1\frac{2}{3}\right)^{^2}\)

Answer 1

[Greninja]

a) \(\left|-\frac{6}{7}\right|\div\left(-2\right)^3-\sqrt{\frac{9}{16}}\)

\(=\frac{6}{7}\div\left(-8\right)-\frac{3}{4}\)

\(=\frac{-3}{28}-\frac{3}{4}\)

\(=\frac{-6}{7}\)

b) \(-5\frac{5}{9}\div\left(-1\frac{3}{4}\right)+4\frac{5}{9}\div\left(-1\frac{3}{4}\right)\)

\(=\left(-5\frac{5}{9}+4\frac{5}{9}\right)\div\left(-1\frac{3}{4}\right)\)

\(=\left(-5+\frac{5}{9}+4+\frac{5}{9}\right)\div\frac{-7}{4}\)

\(=\left(-1+\frac{10}{9}\right).\frac{-4}{7}\)

\(=\frac{1}{9}.\frac{-4}{7}\)

\(=\frac{-4}{63}\)

c) \(-63,99-\left(\frac{4}{9}-63,99\right)-\left(-1\frac{2}{3}\right)^2\)

\(=-63,99-\frac{4}{9}+63,99-\left(\frac{-5}{3}\right)^2\)

\(=-63,99-\frac{4}{9}+63,99-\frac{25}{9}\)

\(=\left(-63,99+63,99\right)-\left(\frac{4}{9}+\frac{25}{9}\right)\)

\(=-\frac{29}{9}\)