Question

[Huy Khanh 6B]

bài 1, so sanh

a,\(\frac{2}{2^2}+\frac{2}{3^2}+\frac{2}{4^2}+...+\frac{2}{10^2}\) và 1

b,\(\frac{2}{2^2}+\frac{2}{4^2}+\frac{2}{6^2}+\frac{8}{2^2}+\frac{2}{10^2}+\frac{2}{12^2}\)và1