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\(\dfrac{1997\times1996-1}{1995\times1997+1996}\)
= \(\dfrac{1997\times\left(1995+1\right)-1}{1995\times1997+1996}\)
= \(\dfrac{1997\times1995+1997-1}{1995\times1997+1996}\)
= \(\dfrac{1995\times1997+1996}{1995\times1997+1996}\)
= 1
a/ Gọi A là giá trị của biểu thức trên
\(\Rightarrow A=\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+...+\frac{1}{120}\)
\(\Rightarrow A=\frac{2}{20}+\frac{2}{30}+\frac{2}{42}+...+\frac{2}{240}\)
\(\Rightarrow A=2\left(\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+...+\frac{1}{240}\right)\)
\(\Rightarrow\frac{A}{2}=\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+...+\frac{1}{240}\)
\(\Rightarrow\frac{A}{2}=\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{14.15}+\frac{1}{15.16}\)
\(\Rightarrow\frac{A}{2}=\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{16}\)
\(\Rightarrow\frac{A}{2}=\frac{1}{4}-\frac{1}{16}\)
\(\Rightarrow A=\frac{3}{16}.2=\frac{3}{8}\)
b/ 0,2 x 317 x 7 + 0,14 x 3520 + 33,1 x 14
= 0,2 x 317 x 7 : 10 x 10 + 0,14 x 3520 + 33,1 x 100 x 14 : 100
= 0,2 x 317 x 0,7 x 10 + 0,14 x 3520 + 33,1 x 100 x 0,14
= ( 0,2 x 0,7) x 317 x 10 + 0,14 x 3520 + 3310 x 0,14
= 0,14 x 3170 + 0,14 x 3520 + 3310 x 0,14
= 0,14 x ( 3170 + 3520 + 3310)
= 0,14 x10000
= 1400
Hứa r, k mik nha!
\(\frac{\left(72\times1995-1996\right)\times\left(18-36\div2\right)\times\left(148\div5-7\right)}{1+3+5+...+1993+1995}\)
= \(\frac{\left(72\times1995-1996\right)\times\left(18-18\right)\times\left(148\div5-7\right)}{1+3+5+...+1993+1995}\)
= \(\frac{\left(72\times1995-1996\right)\times0\times\left(148\div5-7\right)}{1+3+5+...+1993+1995}\)
= \(\frac{0}{1+3+5+...+1993+1995}\)
= 0 : (1 + 3 + 5 + ... + 1993 + 1995)
= 0
(72x1995-1996)x(18-36:2)x(148:5-7) / 1+3+5+....+1993+1995
=(72x1995-1996)x0x(148:5-7) / 1+3+5+...+1993+1995
=0 / 1+3+5+...+1993+1995
=0
Tích nha
3/4 x 8/9 x 15/16 x ... x 99/100 x 120/121 = 3 x 8 x 15 x 99 x 120/ 4 x 9 x 16 x 100 x 121
= ( 1 x 3 ) x ( 2 x 4 ) x ( 3 x 5 ) x ... x ( 9 x 11 ) x ( 10 x 12 ) / ( 2 x 2 ) x ( 3 x 3 ) x ( 4 x 4 ) x ... x ( 10 x 10 ) x ( 11 x 11 )
= ( 1 x 2 x 3 x ... x 10 ) x ( 3 x 4 x 5 x ... x 12 ) / ( 2 x 3 x ... x 11 ) x ( 2 x 3 x ... x 11 ) = 12/11x2 = 6/11
Bài 1: 1/3+1/9+1/27+1/81+1/243+1/729
Đặt:
A = 1 + 1/3 + 1/9 + 1/27 + 1/81 + 1/243 + 1/729
Nhân A với 3 ta có:
\(Ax3=3+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}\)
\(\Rightarrow Ax3-S=3-\frac{1}{243}\)
\(\Rightarrow2A=\frac{2186}{729}\)
\(\Rightarrow A=\frac{2186}{729}:2\)
\(\Rightarrow A=\frac{1093}{729}\)
\(\frac{2}{3}\) \(-\) \(\left(\frac{1}{6}+\frac{1}{8}\right)\)
\(=\) \(\frac{2}{3}\) \(-\) \(\frac{7}{24}\)
\(=\) \(\frac{16}{24}\) \(-\) \(\frac{7}{24}\)
\(=\) \(\frac{9}{24}\)
\(=\)\(\frac{3}{8}\)
\(Học\) \(tốt!\)
a) \(\dfrac{1997x1996-1}{1995x1997+1996}=\dfrac{1997x\left(1995+1\right)-1}{1995x1997+1996}\)
\(=\dfrac{1997x1995+1997-1}{1995x1997+1996}=\dfrac{1997x1995+1996}{1995x1997+1996}=1\)
b) \(\dfrac{1997x1996-995}{1995x1997+1002}=\dfrac{1997x\left(1995+1\right)-995}{1995x1997+1002}\)
\(=\dfrac{1997x1995+1997-995}{1995x1997+1002}=\dfrac{1997x1995+1002}{1995x1997+1002}=1\)
a)37/53x23/48x535353/373737x242424/232323
=37/53x23/48x53/37x24/23
=851/2544x1272/851
=1/2
