Question

[Nguyễn Quý Trung]

a) \(\left(x-2\right)\left(x+1\right)< 0\)

b) \(\left(x+\dfrac{1}{3}\right)\left(x-1\right)\)> hoặc = 0

Answer 1

[Nguyễn Lê Phước Thịnh]

a: Ta có: \(\left(x-2\right)\left(x+1\right)< 0\)

\(\Leftrightarrow-1< x< 2\)

b: Ta có: \(\left(x+\dfrac{1}{3}\right)\left(x-1\right)\ge0\)

\(\Leftrightarrow\left[{}\begin{matrix}x\le-\dfrac{1}{3}\\x\ge1\end{matrix}\right.\)