Question

[Phan Thảo Hiền]

A= 3.\(\frac{1}{117}\).\(\frac{1}{119}\)-\(\frac{4}{117}\).5.\(\frac{118}{119}\)-\(\frac{5}{117.118}\)+\(\frac{8}{39}\)

Đặt a=\(\frac{1}{117}\); b=\(\frac{1}{119}\)

Answer 1

[Phan Lê Linh Chi]

A=(3+a)b-4a(5+1-b)-5ab+24a

  =3b+ab-24a+4ab-5ab+24a

  =3b

  =3/119