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a)|0|+|45|+(-|-455)|+|796|
= 0+45+(-455)+796
=45-455+796
=-410+796
=386
b)-|-33|+(-12)+18+|45-40|-57
=-33-12+18+|5|-57
=-45+18-5-57
=-33-5-57
=-38-57
=-95
c)|40-37|-|13-52|
=|13|-|-39|
=13-39
=-38
|0| + |45| + (-|-455)| + |-796|
= 0 + 45 - 455 + 796
= 386
-|-33 | + (-12) + 18 + |45 - 40| - 57
= -33 - 12 + 18 + 5 - 57
= -79
|40 - 37| - |13 - 52|
= |3| - |-39|
= 3 - 39
= -36
ℓ. 500 – {5[409 – (2³.3 – 21)²] + 10³} : 15
= 500 - {5[409-(8.3-21)2]+103}:15
= 500-{5[409-(24-21)2]+1000}:15
= 500-{5[409-32]+1000}:15
= 500-{5[409-9]+1000}:15
= 500-{[5.400]+1000}:15
= 500-{2000+1000}:15
= 500-3000:15
= 500-200
= 300
m. 67 – [8 + 7.3² – 24 : 6 + (9 – 7)³] : 15
= 67 – [8 + 7.9 – 4 + 23] : 15
= 67 – [8 + 63 – 4 + 8] : 15
= 67 – [71 – 4 + 8] : 15
= 67 – [67 + 8] : 15
= 67 – 75 : 15
= 67 – 5
= 62
n. (–23) + 13 + (–17) + 57
= (–10) + [(–17) + 57]
= (–10) + 40
= 30
o. (–123) + |–13| + (–7)
= [(–123) + (–7)] + |–13|
= (–130) + 13
= (–117)
p. |–10| + |45| + (–|–455|) + |–750|
= 10 + 45 + (–455) + 750
= (10 + 45 + 750) + (–455)
= 805 + (–455)
= 350
q. –|–33| + (–15) + 20 – |45 – 40| – 57 = (–33) + (–15) + 20 – |5| – 57 = (–48) + (20 + 5 + 57) = (–48) + 82 = 34 h. 9.|40 – 37| – |2.13 – 52| = 9.|3| – |26 – 52| = 9.3 – |–26| = 27 – 26 = 1a)48.45+55.48=(45+55).48=100.48=4800
b)57.37+57.23+57.40=57.(23+37+40)=57.100=5700
c)25.5.4.17.2=(25.4).(5.17.2)=100.170=17000
d)127.45+55.127-27.100=127.(45+55)-(27.100)=127.100-27.100=(127-27).100=100.100=10000
e)543+165+457+35=(543+457)+(165+35)=1000+200=1200
g)13.58.4+32.6.2+52.10=(52.58)+(52.32)+52.10=52.(58+32+10)=52.100=5200
h)25.5.4.17.2=(25.4).(17.2.5)=100.170=17000
k)(3737.43-4343.37):(2+4+6+...+100)=(37.101.43-43.101.37):(2+4+6+...+100)=0.(2+4+6+...+100)=0
i)1+5+9+...+29+33+37=(1+37)+(5+33)+...=190
a=4800
b=5700
c=17000
d=10000
e=1200
...
phần còn lại bạn tự làm nhé
a) \(\left(-23\right)+13\left(-17\right)+57\)
\(=\left(-23\right)+\left(-221\right)+57\)
\(=-23-221+57\)
\(=-\left(23+221\right)+57\)
\(=-244+57\)
\(=-\left(244-57\right)\)
\(=-187\)
b) \(\left(-26\right)+\left(-6\right)+\left(-75\right)+\left(-50\right)\)
\(=-26-6-75-50\)
\(=-\left(26+6\right)-75-50\)
\(=-32-75-50\)
\(=-\left(32+75\right)-50\)
\(=-107-50\)
\(=-\left(107+50\right)\)
\(=-157\)
c) \(14+6+\left(-9\right)+\left(-14\right)\)
\(=14+6-9-14\)
\(=20-9-14\)
\(=11-14\)
\(=-3\)
d) \(\left(-123\right)+\left|13\right|+\left(-7\right)\)
\(=-123+13-7\)
\(=-\left(123-13\right)-7\)
\(=-110-7\)
\(=-\left(110+7\right)\)
\(=-117\)
e) \(\left|0\right|+\left|45\right|+\left(-\left|-455\right|\right)+\left|-796\right|\)
\(=0+45+\left(-455\right)-796\)
\(=45-455-796\)
\(=-410-796\)
\(=-\left(410+796\right)\)
\(=-1206\)
f) \(-\left|-33\right|+\left(-12\right)+18+\left|45-40\right|-57\)
\(=-33-12+18+\left|5\right|-57\)
\(=-\left(33+12\right)+18+5-57\)
\(=-45+18+5-57\)
\(=-\left(45-18\right)+5-57\)
\(=-27+5-57\)
\(=-\left(27-5\right)-57\)
\(=-22-57\)
\(=-\left(22+57\right)\)
\(=-79\)
Ta có: \(B=\dfrac{11}{13}\cdot\dfrac{40}{13}+\dfrac{37}{5}:\dfrac{7}{33}-\left(\dfrac{11}{13}+\dfrac{33}{7}:\dfrac{5}{2}\right)\)
\(=\dfrac{440}{169}+\dfrac{37}{5}\cdot\dfrac{33}{7}-\dfrac{11}{13}-\dfrac{33}{7}\cdot\dfrac{2}{5}\)
\(=\dfrac{297}{169}+\dfrac{33}{7}\cdot\left(\dfrac{37}{5}-\dfrac{2}{5}\right)\)
\(=\dfrac{297}{169}+\dfrac{33}{7}\cdot7\)
\(=\dfrac{297}{169}+33=\dfrac{5874}{169}\)
a)-|-33|+(-12)+18+|45-40|-57
=-33-12+18+|5|-57
=-45+18+5-57
=-27+5-57
=-22-57
=-79
b)|40-37|-|13-52|
=|3|-|-39|
=3-39
=-36