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13/15-(y.4/15-2/9).3/5=1/5
(y.4/15-2/9).3/5=13/15-1/5
(y.4/15-2/9).3/5=2/3
y.4/15-2/9=2/3:3/5
y.4/15-2/9=10/9
y.4/15=10/9+2/9
y.4/15=4/3
y=4/3:4/15
y=5
Những chỗ có dấu "." thì thay bằng dấu nhân
a, 3/5 - 1/15 x 10/13
= 3/5 - 2/39
= 117/195 - 10/195
= 107/195
b, (3/5 - 3/20) x 4/5
= (12/20 - 3/20) x 4/5
= 9/20 x 4/5
= 9/25
Chúc bạn học tốt
1.
7/15:(1/2-9/10xX)-1/6=13/6
=>7/15:(1/2-9/10xX)=13/6+1/6
=>7/16:(1/2-9/10xX)=7/3
=>1/2-9/10xX=7/16:7/3
=>1/2-9/10xX=3/16
=>9/10xX=1/2-3/16
=>9/10xX=5/16
=>X=5/16:9/10
=>X=25/72
\(A=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{13.15}\) (DẤU ''.''LÀ DẤU NHÂN NHA P)
\(A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{15}\)
\(A=1+\left(-\frac{1}{3}+\frac{1}{3}\right)+\left(-\frac{1}{5}+\frac{1}{5}\right)+\left(-\frac{1}{7}+\frac{1}{7}\right)+...+\left(-\frac{1}{13}+\frac{1}{13}\right)-\frac{1}{15}\)
\(A=1-\frac{1}{15}\)
A=\(\frac{14}{15}\)
a)\(2-\frac{1}{10.9}-\frac{1}{9.8}-\frac{1}{8.7}-.....-\frac{1}{3.2}-\frac{1}{2.1}=2-\left(\frac{1}{10.9}+\frac{1}{9.8}+\frac{1}{8.7}+....+\frac{1}{3.2}+\frac{1}{2.1}\right)\)
\(=2-\left(\frac{1}{10}-\frac{1}{9}+\frac{1}{9}-\frac{1}{8}+\frac{1}{8}-\frac{1}{7}+....+\frac{1}{3}-\frac{1}{2}+\frac{1}{2}-1\right)\)
\(=2-\left(\frac{1}{10}-1\right)=2-\frac{-9}{10}=\frac{29}{10}\)
b)\(\frac{5}{2.8}+\frac{5}{8.14}+\frac{5}{14.20}+\frac{5}{20.26}+\frac{5}{26.32}=5\left(\frac{1}{2.8}+\frac{1}{8.14}+\frac{1}{14.20}+\frac{1}{20.26}+\frac{1}{26.32}\right)\)
\(=5\left[\frac{1}{6}\left(\frac{1}{2}-\frac{1}{8}+\frac{1}{8}-\frac{1}{14}+\frac{1}{14}-\frac{1}{20}+\frac{1}{20}-\frac{1}{26}+\frac{1}{26}-\frac{1}{32}\right)\right]\)
\(=5\left[\frac{1}{6}\left(\frac{1}{2}-\frac{1}{32}\right)\right]=5\left(\frac{1}{6}.\frac{15}{32}\right)=5.\frac{5}{64}=\frac{25}{64}\)