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\(135-5\cdot\left(x+4\right)=35\)
\(5\cdot\left(x+4\right)=135-35\)
\(5\cdot\left(x+4\right)=100\)
\(x+4=100:5\)
\(x+4=20\)
\(x=20-4\)
\(x=16\)
b) \(25+3\cdot\left(x-8\right)=106\)
\(3\cdot\left(x-8\right)=106-25\)
\(3\cdot\left(x-8\right)=81\)
\(x-8=81:3\)
\(x-8=27\)
\(x=27+8\)
\(x=35\)
c) \(3^2\cdot\left(x+4\right)-5^2=5\cdot2^2\)
\(9\cdot\left(x+4\right)-25=5\cdot4\)
\(9\cdot\left(x+4\right)-25=20\)
\(9\cdot\left(x+4\right)=20+25\)
\(9\cdot\left(x+4\right)=45\)
\(x+4=45:9\)
\(x+4=5\)
\(x=5-4\)
\(x=1\)
Chúc bạn học tốt!!!!!!!!!!!!!!!!!!!!
140 : ( x - 8 ) = 7
x - 8 = 140 : 7 = 20
x = 20 + 8
x = 28
* 140 : (X-8)=7
X-8=140:7
X-8=20
x=20+8
x=28
Vậy X =28
* 4(X+41)=400
X+41=400:4
X+41=100
X=100-41
X=59
Vậy x=59
*135-5(X+4)135
5(X+4)=135-35
5(X+4)=100
X+4=100:5
X+4=20
X=20-4
X=16
Vậy X = 16
a) 135 - 5(x + 4) = 35
<=> 135 - 5x - 20 = 35
<=> 115 - 5x = 35
<=> 5x = 115 - 35
<=> 5x = 80
<=> x = 16
b) 25 + 3 (x - 8) = 106
=> 3 ( x - 8) = 106 - 25
=> 3 ( x - 8) = 81
=> ( x - 8) = 81: 3
=> x - 8 = 27
=> x = 27 + 8
=> x = .......
m, 2(x-51)=2.2^3+20
2(x-51)=2.6+20
2(x-51)=32
x-51=32:2
x-51=16
x =16+51
x =67
n, 450:(x-19)=50
x-19 =450:50
x-19 =9
x =9+19
x =28
o, 4(x-3)=7^2-1^10
4(x-3)=49-1
4(x-3)=48
x-3 =48:4
x-3 =12
x =12+3
x =15
p, 135-5(x+4)=35
5(x+4) =135-35
5(x+4) =100
x+4 =100:5
x+4 =20
x =20-4
x =16
q, 25+3(x-8)=106
3(x-8) =106-25
3(x-8) =81
x-8 =81:3
x-8 =27
x =27+8
x =35
r, 3^2(x+4)-5^2=5.2^2
9(x+4)-25=20
9(x+4) =20+25
9(x+4) =45
x+4 = 45:9
x+4 =5
x =5-4
x =1
p, 135 - 5(x+4) = 35
⇒ 5(x+4) = 135 - 35
⇒ 5(x+4) = 100
x + 4 = 100 : 5
x + 4 = 20
x = 20 - 4
x = 16
Vậy : x=16
a. 25 + 3(x-8) = 106
3(x-8) = 106 - 25 = 81
x -8 = 81 : 3 = 27
x = 27 +8 = 35
b. 32(x +4) - 52 = 5.52
9(x+4) - 25 = 5.25 = 125
9(x+4) = 125 + 25 = 150(Đề sai)
\(a,25+3\left(x-8\right)=106\\ 3\left(x-8\right)=81\\ x-8=27\\ x=35\)
\(a,3\cdot x-15=x+35\)
\(\Rightarrow3x-x=35+15\)
\(\Rightarrow 2x=50\)
\(\Rightarrow x = 50:2\)
\(\Rightarrow x= 25\)
\(b,(8x-16)(x-5)=0\)
\(+, TH1: 8x-16=0\)
\(\Rightarrow8x=16\)
\(\Rightarrow x = 16:8\)
\(\Rightarrow x=2\)
\(+,TH2: x-5=0\)
\(\Rightarrow x =5\)
\(c,x(x+1)=2+4+6+8+10+...+2500\) \(^{\left(1\right)}\)
Đặt \(A=2+4+6+8+10+...+2500\)
Số các số hạng của \(A\) là: \(\left(2500-2\right):2+1=1250\left(số\right)\)
Tổng \(A\) bằng: \(\left(2500+2\right)\cdot1250:2=1563750\)
Thay \(A=1563750\) vào \(^{\left(1\right)}\), ta được:
\(x\left(x+1\right)=1563750\)
\(\Rightarrow x\left(x+1\right)=1250\cdot1251\)
\(\Rightarrow x =1250\)
#\(Toru\)
1. 11(x-9)=77
x-9=7
x=16
2. 4(x-3)=48
x-3=12
x=15
3.3(x-8)=81
(x-8)=27
x=35
a) 135 - 5 (x + 4) = 35
5(x+4)=135-35
5(x+4)=100
x+4=100:5
x+4=20
x=20-4
x=16
b)25 + 3 (x - 8) = 106
3 (x - 8)=106-25
3 (x - 8)=81
x-8=81:3
x-8=27
x=27+8
x=35
a,5(x+4)=135-35
5(x+4)=100
x+4=100:5
x+4=20
x=20-4
x=16
b,3(x-8)=106-25
3(x-8)=81
x-8=81:3
x-8=27
x=27+8
x=35