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\(\frac{-11}{12}.x+0,25=\frac{5}{6}\)
\(\frac{-11}{12}.x=\frac{5}{6}-\frac{1}{4}=\frac{7}{12}\)
\(x=\frac{7}{12}:\frac{-11}{12}=\frac{7}{12}.\frac{12}{-11}\)
\(x=\frac{7}{11}\)
a. \(x=\dfrac{-2}{15}-\dfrac{3}{10}\)
\(x=\dfrac{-13}{30}\)
b. \(\dfrac{-11}{12}x+\dfrac{1}{4}=\dfrac{5}{6}\)
\(\dfrac{-11}{12}x=\dfrac{5}{6}-\dfrac{1}{4}\)
\(\dfrac{-11}{12}x=\dfrac{7}{12}\)
\(x=\dfrac{7}{12}:\dfrac{-11}{12}\)
\(x=\dfrac{-7}{11}\)
c:=>2003x+2005003=2004
=>2003x=-2002999
hay \(x\in\varnothing\)
\(\dfrac{-11}{12}.x+0,25=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{-11}{12}.x=\dfrac{5}{6}-0,25\)
\(\Rightarrow\dfrac{-11}{12}.x=\dfrac{7}{12}\)
\(\Rightarrow x=\dfrac{7}{12}:\dfrac{-11}{12}\)
\(\Rightarrow x=\dfrac{-7}{11}\)
Vậy...........
-11/12.x+0.25=5/6 (1)
<=> -11/12.x=5/6-0.25
<=>-11/12.x=7/12
<=>x= 7/12:(-11/12)
<=>x=84/-132=
Vậy nghiệm của phương trình (1) là:
S={-7/11}
a: \(\dfrac{7}{4}+\dfrac{-3}{5}=\dfrac{35-12}{20}=\dfrac{23}{20}\)
d: \(\left(-\dfrac{1}{4}\right)^2\cdot\dfrac{4}{11}+\dfrac{7}{11}\cdot\left(-\dfrac{1}{4}\right)^2=\dfrac{1}{16}\)
\(\dfrac{7}{4}+\dfrac{-3}{5}=\dfrac{35}{20}+\dfrac{-12}{20}=\dfrac{23}{20}\)
a, 11/13 - ( 5/42 - x ) = - (5/28 - 11/13)
11/13 - (5/42 - x) = - 5/28 + 11/13
- (5/42 - x) + 5/28 = -11/13 + 11/13
- 5/42 + x + 5/28 = 0
- 5/42 + x = 0 - 5/28
- 5/42 + x = - 5/28
x = -5/28 +5/42
x = - 5/84
b, / x + 4/15 \ - / - 3,75 \ = - / - 2,15 \
./ x + 4/15 \ - 3,75 = - 2,15
/ x + 4/15 \ = -2,15 + 3,75
/ x + 4/15 \ = 1,6
x + 4 / 15 = 1,6 hoặc x+ 4/15 = - 1,6
x = 1,6 - 4/15 x = - 1,6 -4/15
x = 4/3 x = -28/15
Vậy x = 4/3 hoặc x = - 28/15
c, ( 0,25 - 30% x ) . 1/3 = 1/4 - 31/6
( 1/4 - 3/10 x ) . 1/3 = - 59/12
( 1/4 - 3/10 x ) = - 59/12 : 1/3
1/4 - 3/10 x = - 59/4
3/10 x = 1/4 + 59/4
3/10 x = 15
x = 15 : 3/10
x = 50
d, ( x - 1/2 ) : 1/3 + 5/7 = 68/7
( x - 1/2 ) : 1/3 = 68/7 - 5/7
( x - 1/2 ) : 1/3 = 63/7
( x - 1/2 ) = 63/7 . 1/3
x -1/2 = 3
x = 3 + 1/2
x = 7/2
a)\(\frac{-11}{12}.x+0,25=5\)
\(\Rightarrow-\frac{11}{12}.x=5-0,25=\frac{19}{4}\)
\(\Rightarrow-\frac{11}{12}.x=\frac{19}{4}\)
\(\Rightarrow x=\frac{-57}{11}\)
b)\(\left(x-1\right)^5=-32=-2^5\)
\(\Rightarrow\left(x-1\right)=-2\)
\(\Rightarrow x=-2+1=-1\)
a ) - 11 / 12 x X + 0 , 25 = 5
- 11 / 12 x X = 4 , 75
X = - 57 / 11
b ) ( x - 1 ) 5 = -32
( x - 1 ) 5 = ( - 2 ) 5
=> x - 1 = - 2
x = -2 + 1
x = -1