Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bn ơi đề bài có nhầm ko vậy
Ko có kết quả ak
Bn nên vt đề bài rõ hơn đi
Thế này thì ko tìm đc x đâu
Tk mk nha
c) (8705 + 5235) – 5x = 3885
13940 – 5x = 3885
5x = 13940 – 3885
5x = 10055
x = 10055 : 5 = 2011
a) 2011 : { 639 : [ 316 – ( 78 + 25 )] : 3 }
= 2011 : { 639 : [ 316 – 103 ] : 3}
= 2011 : ( 639 : 213 : 3 ) = 2011 : (3 : 3 ) = 2011 : 1 = 2011
b) ( 3x – 2 3 ) . 7 = 7 4
3x – 8 = 7 4 : 7
3x – 8 = 7 3
3x – 8 = 343
3x = 343 + 8
3x = 351
x = 351 : 3 = 117
c) (8705 + 5235) – 5x = 3885
13940 – 5x = 3885
5x = 13940 – 3885
5x = 10055
x = 10055 : 5 = 2011
a) 2011 : { 639 : [ 316 – ( 78 + 25 )] : 3 }
= 2011 : { 639 : [ 316 – 103 ] : 3}
= 2011 : ( 639 : 213 : 3 ) = 2011 : (3 : 3 ) = 2011 : 1 = 2011
b) ( 3x – 23) . 7 = 74
3x – 8 = 74 : 7
3x – 8 = 73
3x – 8 = 343
3x = 343 + 8
3x = 351
x = 351 : 3 = 117
c) (8705 + 5235) – 5x = 3885
13940 – 5x = 3885
5x = 13940 – 3885
5x = 10055
x = 10055 : 5 = 2011
Trl:
a) \(2011:\left\{639:\left[316-\left(78+25\right)\right]:3\right\}\)
\(=2011:\left\{639:\left[316-103\right]:3\right\}\)
\(=2011:\left\{639:213:3\right\}\)
\(=2011:1\)
\(=2011\)
b) \(\left(3x-23\right).7=74\)
\(\Rightarrow3x-23=74:7\)
\(\Rightarrow3x-23=10,5\)
\(\Rightarrow3x=10,5+23\)
\(\Rightarrow3x=33,5\)
\(\Rightarrow x=33,5:3\)
\(\Rightarrow11,1\)( Câu này sai đề nha )
c) \(\left(8705+5235\right)-5x=3885\)
\(\Rightarrow13940-5x=3885\)
\(\Rightarrow5x=10055\)
\(\Rightarrow x=10055:5\)
\(\Rightarrow x=2011\)
\(\dfrac{5x}{1.6}+\dfrac{5x}{6.11}+\dfrac{5x}{11.16}+\dfrac{5x}{16.21}+\dfrac{5x}{21.26}+\dfrac{5x}{26.31}=1\)
\(=x\left(\dfrac{5}{1.6}+\dfrac{5}{6.11}+\dfrac{5}{11.16}+\dfrac{5}{16.21}+\dfrac{5}{21.26}+\dfrac{5}{26.31}\right)=1\)
\(=x\left(1-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{26}+\dfrac{1}{26}-\dfrac{1}{31}\right)=1\)
\(=x\left(1-\dfrac{1}{31}\right)=1\)
\(\Rightarrow x=1:\left(1-\dfrac{1}{31}\right)=\dfrac{31}{30}\)
\(\left(\frac{5}{2.7}+\frac{5}{7.12}+\frac{5}{17.22}+\frac{5}{22.27}+\frac{5}{27.32}\right)x=945\)
\(\left(\frac{7-2}{2.7}+\frac{12-7}{7.12}+\frac{17-12}{12.17}+\frac{22-17}{17.22}+\frac{27-22}{22.27}+\frac{32-27}{27.32}\right)x=945\)
\(\left(\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{12}+...+\frac{1}{27}-\frac{1}{32}\right)x=945\)
\(\left(\frac{1}{2}-\frac{1}{32}\right)x=945\Leftrightarrow\frac{15}{32}x=945\Leftrightarrow x=945:\frac{15}{32}=2016\)
\(5^x+5^{x+1}+5^{x+2}+5^{x+3}=1+2+3+...+87+88-4^2\)
=>\(5^x+5^x\cdot5+5^x\cdot25+5^x\cdot125=88\cdot\dfrac{\left(88+1\right)}{2}-16\)
=>\(156\cdot5^x=44\cdot89-16=3900\)
=>\(5^x=\dfrac{3900}{156}=25\)
=>x=2
(8705+5235)-5x= 3885
13940-5x = 3885
5x = 13940-3885
5x = 10055
x = 10055:5
x = 2011
(8705 + 5235) - 5x = 3885
=> 13940 - 5x = 3885
=> 5x = 13940 - 3885
=> 5x = 10055
=> x = 2011