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`@` `\text {Ans}`
`\downarrow`
`c)`
`( 34 - 2x ) . ( 2x - 6 ) = 0`
`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
Vậy, `x \in {17; 3}`
`d)`
`( 2019 - x ) . ( 3x - 12 ) =0` `?`
`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)
Vậy, `x \in {2019; 4}`
`e) `
`57 . ( 9x - 27 ) = 0`
`=>`\(9x-27=0\div57\)
`=> 9x - 27 = 0`
`=> 9x = 27`
`=> x = 27 \div 9`
`=> x = 3`
Vậy, `x = 3`
`f)`
`25 + ( 15 - x ) = 30`
`=> 15 - x = 30 - 25`
`=> 15 - x = 5`
`=> x = 15 -5 `
`=> x = 10`
Vậy, `x = 10`
`g) `
`43 - ( 24 - x ) = 20`
`=> 24 - x = 43 - 20`
`=> 24 - x = 23`
`=> x = 24 - 23`
`=> x = 1`
Vậy, `x = 1`
`h) `
`2 . ( x - 5 ) - 17 = 25`
`=> 2 ( x - 5) = 25+17`
`=> 2 ( x - 5) = 42`
`=> x - 5 = 42 \div 2`
`=> x - 5 = 21`
`=> x = 21 + 5`
`=> x = 26`
Vậy, `x = 26`
`i)`
`3 . ( x + 7 ) - 15 = 27`
`=> 3(x + 7) = 27 + 15`
`=> 3(x + 7) = 42`
`=> x +7 = 42 \div 3`
`=> x + 7 = 14`
`=> x = 14 - 7`
`=> x = 7`
Vậy, `x = 7`
`j)`
`15 + 4 . ( x - 2 ) = 95`
`=> 4(x - 2) = 95 - 15`
`=> 4(x - 2) = 80`
`=> x - 2 = 80 \div 4`
`=> x - 2 = 20`
`=> x = 20 + 2`
`=> x = 22`
Vậy, `x = 22`
`k)`
`20 - ( x + 14 ) = 5`
`=> x + 14 = 20 - 5`
`=> x + 14 = 15`
`=> x = 15 - 14`
`=> x = 1`
Vậy, `x = 1`
`l) `
`14 + 3 . ( 5 - x ) = 27`
`=> 3(5 - x) = 27 - 14`
`=> 3(5 - x) = 13`
`=> 5 - x = 13 \div 3`
`=> 5 - x = 13/3`
`=> x = 5- 13/3`
`=> x = 2/3`
Vậy, `x = 2/3.`
`@` `\text {Kaizuu lv uuu}`
ta có :
812x .27x=95
(34)2x.(33)x=(32)5
38x.33x=310
311x=310
->11x=10
->x=\(\frac{10}{11}\)
Vậy x=\(\frac{10}{11}\)
812x .27x =95
\(\Leftrightarrow\)38x . 33x=95
\(\Leftrightarrow\)311x= 310
\(\Leftrightarrow\)11x = 10
\(\Leftrightarrow\)x= 10/11
1) \(\left(-27\right).\left(-28+128\right)=-27.100=-2700\)
2a)\(\left(x-3\right)\left(2x+6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\2x+6=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
b) \(\left(2x-1\right)^2=81\)
\(\sqrt{\left(2x-1\right)^2}=9\)
\(\left|2x-1\right|=9\)
\(\left[{}\begin{matrix}2x-1=9\\2x-1=-9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-4\end{matrix}\right.\)
c) \(\left(2m+5\right)^3=-27\)
\(\sqrt[3]{\left(2m+5\right)^3}=-3\)
\(2m+5=-3\)
\(m=-4\)
d) \(\left(3x-2\right)^3=64\)
tương tự câu c
2x - 3 = 7 3 . ( x + 7 ) = 15 24 . 3 . ( 5 - x ) = 27 15 + 4 . ( x - 2 ) = 95
2x = 3 + 7 x + 7 = 15 : 3 3 . ( 5 - x ) = 27 : 24 4 . ( x - 2 ) = 95 - 15
2x = 10 x + 7 = 5 3 . ( 5 - x ) = 1,125 4 . ( x - 2 ) = 80
x = 10 : 2 x = 5 - 7 5 - x = 1,125 : 3 x - 2 = 80 : 4
x = 5 x = ( -2 ) 5 - x = 0,375 x - 2 = 20
x = 5 - 0,375 x = 20 + 2
x = 4,625 x = 22
a)
(2x-1)4 = 34
=>2x-1 = 3
2x = 3+1
2x = 4
x = 2
b)
(3x-1)3 = 53
=> 3x-1 = 5
3x = 5+1
3x = 6
x = 2
c)
4x-1 . 42 = 45
4x-1 = 45 : 42
4x-1 = 43
=> x-1 = 3
x= 4
d)
3.34 nhỏ hơn hoặc bằng 32x nhỏ hơn hoặc bằng 33 . 35
35 nhỏ hơn hoặc bằng 32x nhỏ hơn hoặc bằng 38
=> 2x = 5 ; 6 ;7; 8
Nếu 2x = 5 thì x = 5:2 (loại)
Nếu 2x = 6 thì x = 3 ( thỏa mãn )
Nếu 2x = 7 thì x = 7: 2 ( loại)
Nếu 2x = 8 thì x = 4 ( thỏa mãn )
=> x= 3:4
a) \(\left(2x-1\right)^4=81\)
\(\left(2x-1\right)^4=3^4\)
\(\Rightarrow2x-1=3\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
vay \(x=2\)
b) \(\left(3x-1\right)^3=125\)
\(\left(3x-1\right)^3=5^3\)
\(\Rightarrow3x-1=5\)
\(\Rightarrow3x=6\)
\(\Rightarrow x=2\)
vay \(x=2\)
c) \(4^{x-1}.16=1024\)
\(4^{x-1}=\frac{1024}{16}\)
\(4^{x-1}=64\)
\(4^{x-1}=4^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
vay \(x=4\)
d) \(3.81\le9^x\le27.243\)
\(3.3^4\le9^x\le3^3.3^5\)
\(3^5\le3^{2x}\le3^8\)
\(\Rightarrow5\le2x\le8\)
\(\Rightarrow\orbr{\begin{cases}2x\le8\\2x\ge5\end{cases}}\Rightarrow\orbr{\begin{cases}x\le4\\x\ge\frac{5}{2}\end{cases}}\Rightarrow\frac{5}{2}\le x\le8\)
vay \(\frac{5}{2}\le x\le8\)
Sai đề k zậy bạn!! Lớp 6 chưa học mũ âm mà
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