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12 tháng 4 2018
a,\(\frac{2}{5}+\frac{3}{4}=\frac{8+15}{20}=\frac{23}{20}\)
\(\frac{7}{12}-\frac{2}{7}+\frac{1}{12}=(\frac{7}{12}+\frac{1}{12})-\frac{2}{7}\)
\(=\frac{2}{3}-\frac{2}{7}=\frac{14-6}{21}=\frac{8}{21}\)
\(\frac{12}{17}-\frac{5}{17}-\frac{4}{17}=\frac{7}{17}-\frac{4}{17}=\frac{3}{17}\)
b,\(675,39+342,14=1017,53\)
\(563,87+403,13-328,35=638,65\)
12 tháng 4 2018
2/5+3/4=23/20
7/12-2/7+1/12=8/21
12/17-5/17-4/173/17
675,39+342,14=1017,53
563,87+403,13-328,35=638,65
LL
3
30 tháng 4 2018
\(\frac{5}{12}\times\frac{2}{3}+\frac{2}{3}\times\frac{7}{12}+\frac{1}{3}\)
\(=\frac{2}{3}\times\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{1}{3}\)
\(=\frac{2}{3}\times1+\frac{1}{3}\)
\(=\frac{2}{3}+\frac{1}{3}\)
\(=1\)
30 tháng 4 2018
\(\frac{5}{12}\times\frac{2}{3}+\frac{2}{3}\times\frac{7}{12}+\frac{1}{3}=\frac{2}{3}\times\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{1}{3}\)
\(=\frac{2}{3}\times\frac{12}{12}+\frac{1}{3}=\frac{2}{3}\times1+\frac{1}{3}=\frac{2}{3}+\frac{1}{3}=\frac{3}{3}=1\)
27 tháng 7 2018
A)6 và 4/5-(1 và 2/3+3 và 4/5)
=6+4/5-1-2/3-3-4/5
=(6-1-3)+(4/5-4/5)-2/3
=2-2/3=1 và 1/3
B)[(19+5/8/7/12)-(13+1/4/7/12)]X4/5
=[(19-13)+(5/8/7/12-1/4/7/12)]X4/5
=[6+3/8/7/12]X4/5
=[6+9/14]X4/5
=93/14 X4/5=186/35
nhớ
PT
2
19 tháng 12 2016
\(y:\frac{3}{8}=\frac{12}{7}\)
\(y=\frac{12}{7}\times\frac{3}{8}\)
\(y=\frac{9}{14}\)
\(y-\frac{7}{2}=1\)
\(y=1+\frac{7}{2}\)
\(y=\frac{9}{2}\)
19 tháng 12 2016
y : \(\frac{3}{8}\)= \(\frac{12}{7}\) y - \(\frac{7}{2}\)= 1
y = \(\frac{12}{7}x\frac{3}{8}\) y = 1 + \(\frac{7}{2}\)
y = \(\frac{9}{14}\) y = \(\frac{9}{2}\)
14 tháng 10 2017
x + 7/12 = 11/6 : 2/1
x + 7/12 = 11/12
x = 11/12 - 7/12
x = 1/3
10 tháng 8 2022
1.3.77−1+3.7.99−3+7.9.1313−7+9.13.1515−9+\frac{19-13}{13.15.19}+13.15.1919−13
=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}=1.31−3.71+3.71−7.91+7.91−9.131+9.131−13.151+13.151−15.191
=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}=1.31−15.191=28595−2851=28594
b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)b,=61.(1.3.76+3.7.96+7.9.136+9.13.156+13.15.196)
làm giống như trên
c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)c,=81.(1.2.31+2.3.41+3.4.51+...+48.49.501)
=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)=161.(1.2.32+2.3.42+3.4.52+...+48.49.502)
=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)=161.(1.2.33−1+2.3.44−2+3.4.55−3+...+48.49.5050−48)
=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)=161.(1.21−2.31+2.31−3.41+3.41−4.51+...+48.491−49.501)
=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}=161.(21−24501)=161.(24501225−24501)=4900153
d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)d,=75.(1.5.87+5.8.127+8.12.157+...+33.36.407)
=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)=75.(1.5.88−1+5.8.1212−5+8.12.1515−8+...+33.36.4040−33)
=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)=75.(1.51−5.81+5.81−8.121+8.121−12.151+...+33.361−36.401)
=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}=75.(51−14401)=75.(1440288−14401)=28841
P/S: . là nhân nha
8 tháng 9 2021
\(\dfrac{4}{9}=\dfrac{44}{99};\dfrac{5}{11}=\dfrac{45}{99};\dfrac{44}{99}< \dfrac{45}{99}\Rightarrow\dfrac{4}{9}< \dfrac{5}{11}\\ \dfrac{2}{3}=\dfrac{8}{12}< \dfrac{11}{2}\\ \dfrac{7}{18}>\dfrac{7}{24}\left(18< 24\right)\\ \dfrac{12}{13}=\dfrac{12\cdot101}{13\cdot101}=\dfrac{1212}{1313}>\dfrac{1010}{1313}\\ \dfrac{2}{5}=\dfrac{2\cdot11}{5\cdot11}=\dfrac{22}{55}\\ \dfrac{6}{7}< 1< \dfrac{7}{6}\)
6 tháng 4 2017
1a) \(\frac{49}{84}-\frac{24}{84}+\frac{7}{84}\)
\(=\frac{8}{21}\)
2b)\(=\frac{72}{99}-\left(\frac{28}{99}+\frac{14}{99}\right)\)
\(=\frac{72}{99}-\frac{42}{99}\)
=\(\frac{30}{99}=\frac{10}{33}\)
c) = 83,45 - ( 30,98 + 42,47 )
= 83,45 - 73,45
= 10
mình làm được rồi đấy nhớ k cho mình nhe
6 tháng 4 2017
7/12-2/7+1/12
=49/84-24/84+7/84
=73/84-7/84
=66/84=22/28
2.
a)72/99-28/99-14/99
=72/99-(28/99+14/99)
=72/99-42/99
=30/99=10/33
83,45-30,98-42,47
=83,45-(30,98+42,47)
=83,45-73,45
=10
7/12 - 2/7 + 1/12
= 25/84 + 1/12
= 8/21
đáp số : 8/21
8/21 nha bạn