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Ta có: \(\frac{15}{14}\left(\frac{14}{9}-\frac{3}{7}\right)-\frac{15}{14}\left(\frac{14}{6}-\frac{3}{7}\right)\)
\(=\frac{15}{14}\left[\left(\frac{14}{9}-\frac{3}{7}\right)-\left(\frac{14}{6}-\frac{3}{7}\right)\right]\)
\(=\frac{15}{14}\left(\frac{14}{9}-\frac{3}{7}-\frac{14}{6}+\frac{3}{7}\right)\)
\(=\frac{15}{14}\left(\frac{14}{9}-\frac{14}{6}\right)\)
\(=\frac{15}{14}\cdot\left(\frac{28}{18}-\frac{42}{18}\right)\)
\(=\frac{15}{14}\cdot\frac{-14}{18}\)
\(=\frac{-15}{18}=-\frac{5}{6}\)
\(A=\dfrac{14}{8.11}+\dfrac{14}{11.14}+\dfrac{14}{14.17}+.....+\dfrac{14}{197.200}\)
\(A=\dfrac{14}{3}\left(\dfrac{1}{8}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{14}+\dfrac{1}{14}-\dfrac{1}{17}+...+\dfrac{1}{197}-\dfrac{1}{200}\right)\)
\(A=\dfrac{14}{3}.\left(\dfrac{1}{8}-\dfrac{1}{200}\right)\)
\(A=\dfrac{14}{3}.\dfrac{24}{200}=\dfrac{28}{25}\)
\(B=\dfrac{7}{15}+\dfrac{7}{35}+\dfrac{7}{63}+...+\dfrac{7}{399}\)
\(B=\dfrac{7}{3.5}+\dfrac{7}{5.7}+\dfrac{7}{7.9}+.....\dfrac{7}{19.21}\)
\(B=\dfrac{7}{2}\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+....+\dfrac{1}{19}-\dfrac{1}{21}\right)\)
\(B=\dfrac{7}{2}.\left(\dfrac{1}{3}-\dfrac{1}{21}\right)\)
\(B=\dfrac{7}{2}.\dfrac{6}{21}=1\)
[-7/12].5/14+9/14.[-7/12]-(-3/4)
= -7/12. ( 5/14 + 9/14) + 3/4
=-7/12. 1 + 3/4
= -7/12+ 3/4
=1/6
\(=\frac{18+3+14}{7}+\frac{8+5+5}{9}=\frac{35}{7}+\frac{18}{9}=5+2=7\)
14 + 6 + (-9) + (-14)
= [ 14 + (-14) ] + [ 6 + (-9) ]
= 0 + - 3
= - 3
= -7 -14= - (7+14)= - 21