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\(\left(5x-1\right)^2+2\left(1-5x\right)\left(4+5x\right)+\left(5x+4\right)^2\)
\(=\left(5x-1\right)^2-2\left(5x-1\right)\left(5x+4\right)+\left(5x+4\right)^2\)
\(=\left[\left(5x-1\right)-\left(5x+4\right)\right]^2\)
\(=\left(5x-1-5x-4\right)^2\)
\(=\left(-5\right)^2\)
\(=25\)
\(\Rightarrow5^x\left(1+5+5^2\right)=3875\\ \Rightarrow5^x=\dfrac{3875}{31}=125=5^3\\ \Rightarrow x=3\)
(5x-1)^2+2(5x-1)(5x+1)+5(2x-1)
=25x^2-10x+1+2(25x^2-1)+10x-5
=25x^2-4+50x^2-2
=75x^2-6
\(\left(5x-1\right)^2+2\left(5x-1\right)\left(5x+1\right)+5\left(2x-1\right)\)
\(=25x^2-10x+1+2\left(25x^2-1\right)+10x-5\)
\(=25x^2-10x+1+50x^2-2+10x-5\)
\(=\left(25x^2+50x^2\right)+\left(10x-10x\right)+\left(1-2-5\right)\)
\(=75x^2-6\)
a, \(-4x+5+2x-1=3\Leftrightarrow-2x=-1\Leftrightarrow x=\dfrac{1}{2}\)
b, \(-2x+2=2\Leftrightarrow x=0\)
c, \(-2x-6=-8\Leftrightarrow x=1\)
a: \(=\dfrac{x^5}{3x}+\dfrac{12x^2}{3x}+\dfrac{5x}{3x}=\dfrac{1}{3}x^4+4x+\dfrac{5}{3}\)
b: \(=\dfrac{-5x^4}{-5x}-\dfrac{15x^3}{5x}+\dfrac{18x}{5x}=x^3-3x^2+\dfrac{18}{5}\)
c: \(=\dfrac{-x^6}{0.5x}+\dfrac{5x^4}{0.5x}-\dfrac{2x^3}{0.5x}=-2x^5+10x^3-4x^2\)
\(C=x^4\left(x-4\right)-x^3\left(x-4\right)+x^2\left(x-4\right)-x\left(x-4\right)+x-1\)
\(C=\left(x-4\right)\left(x^4-x^3+x^2-x\right)+\left(x-1\right)=\left(4-4\right)\left(4^4-4^3+4^2-4\right)+\left(4-1\right)=3\)
5
x
+5
x+2
=650
5^x\left(1+5^2\right)=6505
x
(1+5
2
)=650
5^x\cdot26=6505
x
⋅26=650
5^x=650\text{ : }265
x
=650 : 26
5^x=255
x
=25
5^x=5^25
x
=5
2
\Rightarrow\text{ }x=2⇒ x=2
\(5^x+5^{x+2}=650\)
\(5^x\left(1+5^2\right)=650\)
\(5^x\cdot26=650\)
\(5^x=650\text{ : }26\)
\(5^x=25\)
\(5^x=5^2\)
\(\Rightarrow\text{ }x=2\)