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\(\text{1) -5x - (-3)= 13}\)
\(\Rightarrow-5x=10\)
\(x=10:-5\)
\(x=-2\)
\(\text{2) |x-3| - 7= 13}\)
\(\Rightarrow|x-3|=20\)
\(\Rightarrow\orbr{\begin{cases}x-3=20\\x-3=-20\end{cases}\Leftrightarrow\orbr{\begin{cases}x=23\\x=-17\end{cases}}}\)
\(\text{3) 17- (43 - |x|)= 45}\)
\(\Rightarrow43-|x|=-28\)
\(|x|=71\)
\(\Rightarrow\orbr{\begin{cases}x=71\\x=-71\end{cases}}\)
\(\text{5) (x-2).(x+15)= 0}\)
\(\Rightarrow\orbr{\begin{cases}x-2=0\\x+15=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-15\end{cases}}}\)
4,\(\text{4) (x-3).(x-5) < 0}\)\(\left(x-3\right).\left(x-5\right)< 0\)
\(\Rightarrow\left(x-3\right)\)và \(\left(x-5\right)\)trái dấu
Mà \(\left(x-3\right)>\left(x-5\right)\Rightarrow\left(x-3\right)>0\)và \(\left(x-5\right)< 0\)
\(+,x-3>0\Rightarrow x>3\)
\(+,x-5< 0\Rightarrow x< 5\)
\(\Rightarrow3< x< 5\)
\(\)Mà \(x\in Z\)
\(\Rightarrow x=4\)
học tốt
1<=>-5x+3=13
<=>-5x=10
<=>x=-2
2<=>|x-3|=20
th1:x-3=20
<=>x=23
th2:x-3=-20
<=>x=-17
3,<=>17-43+|x|=45
<=>|x|=71
th1:x=71
th2:x=-71
4<=>x-3<0 x-5>0
<=>x<3 x>5(loại vì ko có số naod vừa lớn hơn 5 và nhỏ hơn 3)
<=>x-3>0 x-5<0
<=>x>3 x<5
=>3<x<5
5,<=>x-2=0 x+15=0
<=>x=2 x=-15
https://www.youtube.com/channel/UCb2H-q6FmW61PgcsL1OGPfw ủng hộ bạn t:))
Bài 1
a) 15 + 4.12 - 3²
=15 + 48 - 9
= 63 - 9
= 54
b) {[(37 + 13) : 5].2 - 45 : 5}.7 - 2022⁰
= [(50 : 5).2 - 9].7 - 1
= (10.2 - 9).7 - 1
= (20 - 9).7 - 1
= 11.7 - 1
= 77 - 1
= 76
Bài 2
a) 13x + 3 = 16
13x = 16 - 3
13x = 13
x = 13 : 13
x = 1
b) 2x - 138 = 2⁴ : 2³
2x = 2 + 138
2x = 140
x = 140 : 2
x = 70
** Bổ sung thêm điều kiện $x,y$ là số nguyên.
Lời giải:
Với $x,y$ nguyên thì $x-2, x-y+5$ cũng là số nguyên. Mà $(x-2)(x-y+5)=11$ nên ta có các TH sau:
TH1:
$x-2=1, x-y+5=11\Rightarrow x=3; y=-3$ (thỏa mãn)
TH2:
$x-2=-1, x-y+5=-11\Rightarrow x=1; y=17$ (thỏa mãn)
TH3:
$x-2=11, x-y+5=1\Rightarrow x=13; y=17$ (thỏa mãn)
TH4:
$x-2=-11; x-y+5=-1\Rightarrow x=-9; y=-3$ (thỏa mãn)
a) 5/17 * 8/-7+8/17*-7/3+-7/3*4/17
-40/119 + 12/17 × -7/3
-40/119 + -28/17 =-236/119
b) -10/13 + 5/17 - 3/13 + 12/17 - 11/20
(5/17+12/17)-(10/13+3/13)-11/20
-11/20
a) 5/17 * 8/-7+8/17*-7/3+-7/3*4/17
-40/119 + 12/17 × -7/3
-40/119 + -28/17 =-236/119
b) -10/13 + 5/17 - 3/13 + 12/17 - 11/20
(5/17+12/17)-(10/13+3/13)-11/20
-11/20
= 28/15 . 3/4 - ( 11/20 + 1/4 ) : 7/3
= 28/15 . 3/4 - 4/5 : 7/3
= 7/5 - 12/35
= 37/35
= \(\dfrac{28}{15}\) . \(\dfrac{3}{4}\) - (\(\dfrac{11}{20}\) + \(\dfrac{1}{4}\)) : \(\dfrac{7}{3}\)
= \(\dfrac{7}{5}\) - (\(\dfrac{11}{20}\) + \(\dfrac{5}{20}\)) : \(\dfrac{7}{3}\)
= \(\dfrac{7}{5}\) - \(\dfrac{16}{20}\) : \(\dfrac{7}{3}\)
= \(\dfrac{7}{5}\) - \(\dfrac{16}{20}\) x \(\dfrac{3}{7}\)
= \(\dfrac{7}{5}\) - \(\dfrac{12}{35}\)
= \(\dfrac{49}{35}\) - \(\dfrac{12}{35}\)
= \(\dfrac{37}{35}\)
Ta có:\(\frac{2017^{18}+1}{2017^{17}+1}>1\)
\(\Rightarrow\frac{2017^{18}+1}{2017^{17}+1}>\frac{2017^{18}+1+2016}{2017^{17}+1+2016}=\frac{2017^{18}+2017}{2017^{17}+2017}\)\(=\frac{2017\left(2017^{17}+1\right)}{2017\left(2017^{16}+1\right)}=\frac{2017^{17}+1}{2017^{16}+1}\)
Vậy \(\frac{2017^{17}+1}{2017^{16}+1}< \frac{2017^{18}+1}{2017^{17}+1}\)
Thanks you nhiều nha,lần sau nhớ giải hộ mình các bài toán khác nữa nha
5.\(-\dfrac{3}{7}+\dfrac{5}{13}+\dfrac{-4}{12}=-\dfrac{103}{273}\)
b.\(-\dfrac{5}{21}+\dfrac{-2}{21}+\dfrac{8}{24}=\dfrac{-5-2}{21}+\dfrac{8}{24}=-\dfrac{7}{21}+\dfrac{8}{24}=-\dfrac{1}{3}+\dfrac{8}{24}=0\)
c.\(\dfrac{5}{13}+\dfrac{-5}{7}+\dfrac{-20}{41}+\dfrac{8}{13}+\dfrac{-21}{41}=\left(\dfrac{5}{13}+\dfrac{8}{13}\right)+\left(\dfrac{-20}{41}+\dfrac{-21}{41}\right)+-\dfrac{5}{7}=1-1-\dfrac{5}{7}=-\dfrac{5}{7}\)
Ta có: \(5.\left|x\right|=\left|-2017\right|+\left|13\right|\)
\(5.\left|x\right|=2017+13\)
\(5.\left|x\right|=2030\)
\(\left|x\right|=406\)
\(\Rightarrow x\in\left\{-406;406\right\}\)
Sắp thi rùi, chúc bn hok "tuốt" nha^^