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`x/(2*2)+x/(3*4)+x/(6*4)+x/(8*5)+x/(10*6)=5`
`x/4 +x/12 +x/24 +x/45 + x/60 =5`
`x(1/4 +1/12 +1/24 +1/40 +1/60)=5`
`x( (30+10+5+3+2)/120 ) =5`
`x *50/120 =5`
`x = 5 *120/50 =12`
a) \(\dfrac{1}{2}-\left(x+\dfrac{1}{3}\right)=\dfrac{5}{6}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{1}{2}-\dfrac{5}{6}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{-1}{3}\)
\(\Rightarrow x=\dfrac{-1}{3}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{-2}{3}\)
b)\(\dfrac{3}{4}-\left(x+\dfrac{1}{2}\right)=\dfrac{4}{5}\)
\(\Rightarrow x+\dfrac{1}{2}=\dfrac{3}{4}-\dfrac{4}{5}\)
\(\Rightarrow x+\dfrac{1}{2}=\dfrac{-1}{20}\)
\(\Rightarrow x=\dfrac{-1}{20}-\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{-11}{20}\)
c) \(\dfrac{3}{35}-\left(\dfrac{3}{5}+x\right)=\dfrac{2}{7}\)
\(\Rightarrow\dfrac{3}{5}+x=\dfrac{3}{35}-\dfrac{2}{7}\)
\(\Rightarrow\dfrac{3}{5}+x=\dfrac{-1}{5}\)
\(\Rightarrow x=\dfrac{-1}{5}-\dfrac{3}{5}\)
\(\Rightarrow x=\dfrac{-4}{5}\)
d)\(\dfrac{2}{3}.x=\dfrac{4}{27}\)
\(\Rightarrow x=\dfrac{4}{27}:\dfrac{2}{3}\)
\(\Rightarrow x=\dfrac{2}{9}\)
e) \(\dfrac{-3}{5}.x=\dfrac{21}{10}\)
\(\Rightarrow x=\dfrac{21}{10}:\dfrac{-3}{5}\)
\(\Rightarrow x=\dfrac{-7}{2}\)
a: =-5/6-3/7=-35/42-18/42=-53/42
b: =18/45-20/45=-2/45
c: =-24/35
d: =2/3x-5/4=-10/12=-5/6
\(\dfrac{-5}{6}+\dfrac{3}{7}=\dfrac{-5\times7+3\times6}{6\times7}=\dfrac{-17}{42}.\)
\(\dfrac{2}{5}-\dfrac{4}{9}=\dfrac{2\times9-4\times5}{5\times9}=\dfrac{-2}{45}.\)
\(\dfrac{-6}{5}\times\dfrac{4}{7}=\dfrac{-6\times4}{5\times7}=\dfrac{-24}{35}.\)
\(\dfrac{2}{3}:\dfrac{-4}{5}=\dfrac{2}{3}\times\dfrac{5}{-4}=\dfrac{-5}{6}.\)
a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)
\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{-5}{12}\)
b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{5}\)
c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)
\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-77}{120}\)
d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{-7}{20}\)
e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)
\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-59}{105}\)
g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-13}{12}\)
\(\frac{4}{5}.x-x-\frac{3}{2}.x+\frac{5}{6}=\frac{1}{2}-\frac{4}{3}\)đề nảy hả
\(\frac{4}{5}x-x-\frac{3}{2}x+\frac{5}{6}=\frac{1}{2}-\frac{4}{3}\)
\(-\frac{1}{5}x-\frac{3}{2}x=-\frac{5}{6}-\frac{5}{6}\)
\(-\frac{17}{10}x=-\frac{10}{6}\)
\(x=\frac{50}{51}\)
`3x-16:2^3=31`
`=>3x-16:8=31`
`=>3x-2=31`
`=>3x=31+2`
`=>3x=33`
`=>x=11`
__
`2^10:2^8+3[4.7+3.4]`
`=2^2+3[4(3+7)]`
`=4+3[4.10]`
`=4+3.40`
`=4+120`
`=124`
__
`4^6:4^3-2^2 . 2^3`
`=4^3-2^5`
`=64-32`
`=32`
__
`141+2^5 . 2^4-3^1 . 3^2`
`=141+2^9-3^3`
`=141+512-9`
`=644`
__
`x+2^5:2^4=4.4^2`
`=>x+2=4^3`
`=>x=64-2`
`=>x=62`
a: =>4/3x=7/9-4/9=1/3
=>x=1/4
b: =>5/2-x=9/14:(-4/7)=-9/8
=>x=5/2+9/8=29/8
c: =>3x+3/4=8/3
=>3x=23/12
hay x=23/36
d: =>-5/6-x=7/12-4/12=3/12=1/4
=>x=-5/6-1/4=-10/12-3/12=-13/12
1) 4*x-0.25=512
4*x = 512+0,25
4*x= 512,25
x=512.25:4=128,0625
nhìu quá ko làm nữa
Khó quá
Tìm x
\(5^2.x-2^4.x=3^4-6.3^2\)
\(25x-16x=81-6.9\)
\(x\left(25-16\right)=81-54\)
\(x.9=27\)
\(x=27\div9\)
\(x=3\)
Vậy \(x=3\).