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23 tháng 7 2022

4x5/6-x=7/12-1/3

= 10/3  - x = 1/4

=  x = 10/3 - 1/4

= x = 37/12

 

23 tháng 7 2022

`4 xx 5/6 - x  =7/12 - 1/3`

`4 xx 5/6 - x  =7/12- 4/12`

`4 xx 5/6 - x  =3/12`

`4 xx 5/6 - x  =1/4`

`10/3 - x  =1/4`

`x=10/3-1/4`

`x=37/12`

10 tháng 6 2015

1> a) \(\frac{5}{7}x4:\frac{5}{9}=\frac{5}{7}:\frac{5}{9}x4=\frac{5}{7}x\frac{9}{5}x4=\frac{9}{7}x4=\frac{9x4}{7}=\frac{36}{7}\)

\(b,8x\frac{2}{3}:\frac{1}{2}=8x\frac{2}{3}x\frac{2}{1}=8x2x\frac{2}{3}=16x\frac{2}{3}=\frac{32}{3}\)

\(c,6:\frac{3}{5}-\frac{7}{6}x\frac{6}{7}=6x\frac{5}{3}-1=10-1=9\)

\(\frac{21}{5}x\frac{10}{11}+\frac{57}{11}=\frac{42}{11}+\frac{57}{11}=\frac{99}{11}=9\)

2) a) \(\frac{35}{9}:x=\frac{35}{6}\)

\(x=\frac{35}{9}:\frac{35}{6}\)

\(x=\frac{35}{9}x\frac{6}{35}\)

\(x=\frac{2}{3}\)

b) \(\left(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}\right)x10-X=0\)

\(\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+.....+\frac{1}{5}-\frac{1}{6}\right)x10-X=0\)

\(\left(\frac{1}{1}-\frac{1}{6}\right)x10-X=10\)

\(\frac{5}{6}x10-X=0\)

\(X=\frac{5}{6}x10=\frac{25}{3}\)

Đúng nha !!!!

10 tháng 6 2015

1/a/\(\frac{5}{7}\cdot4:\frac{5}{9}=\frac{20}{7}:\frac{5}{9}=\frac{20}{7}\cdot\frac{9}{5}=\frac{36}{7}\)

b/\(8\cdot\frac{2}{3}:\frac{1}{2}=\frac{16}{3}:\frac{1}{2}=\frac{16}{3}\cdot\frac{2}{1}=\frac{32}{3}\)

c/\(6:\frac{3}{5}-\frac{7}{6}\cdot\frac{6}{7}=6\cdot\frac{5}{3}-1=10-1=9\)

2/a/\(\frac{35}{9}:x=\frac{35}{6}\)

\(x=\frac{35}{9}:\frac{35}{6}=\frac{35}{9}\cdot\frac{6}{35}\)

\(x=\frac{2}{3}\)

 

b/\(\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}\right)\cdot10-x=0\)

\(\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}\right)\cdot10-x=0\)

\(\left(\frac{30}{60}+\frac{10}{60}+\frac{5}{60}+\frac{2}{30}\right)\cdot10-x=0\)

\(\frac{47}{60}\cdot10-x=0\)

\(\frac{47}{6}-x=0\)

\(x=\frac{47}{6}-0\)

\(x=\frac{47}{6}\)

14 tháng 8 2023

` a,` 

`1/3 + 3/4 xx 5/9 `

 

`=1/3 + (3/4 xx 5/9) `

 

`= 1/3 + 5/12 `

 

`= 4/12 + 5/12`

 

`= 9/12 `

 

`= 3/4 .`

 

`b,`

` 7/12 - 5/4 xx 2/15 `

 

`= 7/12 - (5/4 xx 2/15)`

 

`= 7/12 - 1/6`

 

`= 7/12 - 2/12 `

 

`= 5/12 .`

a: =>1/3*4+1/4*5+...+1/x(x+1)=10/39

=>1/3-1/4+...+1/x-1/x+1=10/39

=>1/3-1/(x+1)=10/39

=>1/(x+1)=13/39-10/39=3/39=1/13

=>x+1=13

=>x=12

b: =>15x=150

=>x=10

c: =>120-5x=45

=>5x=75

=>x=15

30 tháng 7 2023

 mình cảm ơn ạ

30 tháng 5 2023

\(\left(x+\dfrac{1}{2\times3}\right)+\left(x+\dfrac{1}{3\times4}\right)+\left(x+\dfrac{1}{4\times5}\right)+\left(x+\dfrac{1}{5\times6}\right)=\dfrac{25}{3}\)

\(x+\dfrac{1}{2\times3}+x+\dfrac{1}{3\times4}+x+\dfrac{1}{4\times5}+x+\dfrac{1}{5\times6}=\dfrac{25}{3}\)

\(x\times4+\left(\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}\right)=\dfrac{25}{3}\)

\(x\times4+\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}\right)=\dfrac{25}{3}\)

\(x\times4+\left(\dfrac{1}{2}-\dfrac{1}{6}\right)=\dfrac{25}{3}\)

\(x\times4+\dfrac{4}{12}=\dfrac{25}{3}\)

\(x\times4=\dfrac{25}{3}-\dfrac{4}{12}\)

\(x\times4=\dfrac{25}{3}-\dfrac{1}{3}\)

\(x\times4=\dfrac{24}{3}\)

\(x\times4=8\)

\(x=8\div4\)

\(x=2\)

:))

 

 

3 tháng 12 2019

3/4*5/2*7/6

=0.75*2.5*1.16

=2.1875

10 tháng 8 2023

3/4*5/2*7/6

=0.75*2.5*1.16

=2.1875

   
21 tháng 5 2023

`(y+2/9) xx 1/5 = 7/15`

`=> y +2/9 = 7/15 : 1/5`

`=> y +2/9 = 7/15 xx 5`

`=> y +2/9= 35/15`

`=> y= 35/15 -2/9`

`=> y= 7/3 -2/9`

`=> y= 21/9-2/9`

`=> y= 19/9`

Vậy `y=19/9`

__

`yxx(12/7 +4/3) = 5/6`

`=> y xx 64/21 = 5/6`

`=> y= 5/6 : 64/21`

`=> y=5/6 xx 21/64`

`=> y=35/128`

Vậy `y= 35/128`

21 tháng 5 2023

\(\left(y+\dfrac{2}{9}\right)\times\dfrac{1}{5}=\dfrac{7}{15}\)

\(y+\dfrac{2}{9}=\dfrac{7}{15}:\dfrac{1}{5}\)

\(y+\dfrac{2}{9}=\dfrac{7}{15}\times5\)

\(y+\dfrac{2}{9}=\dfrac{7}{3}\)

\(y=\dfrac{7}{3}-\dfrac{2}{9}\)

\(y=\dfrac{21}{9}-\dfrac{2}{9}\)

\(y=\dfrac{19}{9}\)

========================

\(y\times\left(\dfrac{12}{7}+\dfrac{4}{3}\right)=\dfrac{5}{6}\)

\(y\times\left(\dfrac{36}{21}+\dfrac{28}{21}\right)=\dfrac{5}{6}\)

\(y\times\dfrac{64}{21}=\dfrac{5}{6}\)

\(y=\dfrac{5}{6}:\dfrac{64}{21}\)

\(y=\dfrac{5}{6}\times\dfrac{21}{64}\)

\(y=\dfrac{35}{128}\)