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x+y=9 nên x=9-y
\(M=\dfrac{4\left(9-y\right)-9}{3\left(9-y\right)+y}-\dfrac{4y+9}{3y+9-y}\)
\(=\dfrac{36-4y-9}{27-3y+y}-\dfrac{4y+9}{2y+9}\)
\(=\dfrac{4y-27}{2y-27}-\dfrac{4y+9}{2y+9}\)
\(=\dfrac{8y^2+36y-54y-243-\left(8y^2-108y+18y-243\right)}{\left(2y-27\right)\left(2y+9\right)}\)
\(=\dfrac{8y^2-18y-243-8y^2+90y+243}{\left(2y-27\right)\left(2y+9\right)}=\dfrac{72y}{\left(2y-27\right)\left(2y+9\right)}\)
\(\frac{x}{6}=\frac{y}{-7}=\frac{4x+3y}{4\cdot6+3\cdot\left(-7\right)}=\frac{-6}{3}=-2\)
\(\Rightarrow\) x = - 12; y = 14
Cho x-y=9 => x=9+y thay vào B ta được:
B=4(9+y)-9/3(9+y)+y - 4y+9/3y+9+y
B= 36+4y-9/27+4y - 4y+9/4y+9
B= 37+4y/27+4y - 4y+9/4y+9
B= 1-1
B=0
1) \(\Rightarrow\dfrac{x}{8}=\dfrac{y}{12}=\dfrac{z}{15}\)
Áp dụng t/c dtsbn:
\(\dfrac{x}{8}=\dfrac{y}{12}=\dfrac{z}{15}=\dfrac{x-y+z}{8-12+15}=\dfrac{10}{11}\)
\(\Rightarrow\left\{{}\begin{matrix}\dfrac{x}{8}=\dfrac{10}{11}\\\dfrac{y}{12}=\dfrac{10}{11}\\\dfrac{z}{15}=\dfrac{10}{11}\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{80}{11}\\y=\dfrac{120}{11}\\z=\dfrac{150}{11}\end{matrix}\right.\)
2) \(\Rightarrow\left\{{}\begin{matrix}\dfrac{x}{3}=\dfrac{y}{4}\\\dfrac{y}{5}=\dfrac{z}{7}\end{matrix}\right.\) \(\Rightarrow\dfrac{x}{15}=\dfrac{y}{20}=\dfrac{z}{28}\)
Áp dụng t/c dtsbn:
\(\dfrac{x}{15}=\dfrac{y}{20}=\dfrac{z}{28}=\dfrac{2x}{30}=\dfrac{3y}{60}=\dfrac{2x+3y-z}{30+60-28}=\dfrac{136}{62}=\dfrac{68}{31}\)
\(\Rightarrow\left\{{}\begin{matrix}\dfrac{x}{15}=\dfrac{68}{31}\\\dfrac{y}{20}=\dfrac{68}{31}\\\dfrac{z}{28}=\dfrac{68}{31}\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{1020}{31}\\y=\dfrac{1360}{31}\\z=\dfrac{1904}{31}\end{matrix}\right.\)
3) \(\Rightarrow\dfrac{3x-9}{15}=\dfrac{5y-25}{5}=\dfrac{7z+21}{49}\)
Áp dụng t/c dtsbn:
\(\dfrac{3x-9}{15}=\dfrac{5y-25}{5}=\dfrac{7z+21}{49}=\dfrac{3x+5y-7z-9-25-21}{15+5-49}=-\dfrac{45}{29}\)
\(\Rightarrow\left\{{}\begin{matrix}\dfrac{3x-9}{15}=-\dfrac{45}{29}\\\dfrac{5y-25}{5}=-\dfrac{45}{29}\\\dfrac{7z+21}{49}=-\dfrac{45}{29}\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=-\dfrac{138}{29}\\y=\dfrac{100}{29}\\z=-\dfrac{402}{29}\end{matrix}\right.\)
`#3107.101117`
a)
`x \div y \div z = 4 \div 3 \div 9`
`=> x/4 = y/3 = z/9`
`=> x/4 = (3y)/9 = (4z)/36`
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
`x/4 = (3y)/9 = (2z)/8 = (x - 3y + 4z)/(4 - 9 + 36) = 62/31 = 2`
`=> x/4 = y/3 = z/9 = 2`
`=> x = 4*2 = 8` $\\$ `y = 3*2 = 6` $\\$ `z = 9*2 = 18`
Vậy, `x = 8; y = 6; z = 18`
c)
\(x \div y \div z = 1 \div 2 \div 3\)
`=> x/1 = y/2 = z/3`
`=> (4x)/4 = (3y)/6 = (2z)/6`
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
`(4x)/4 = (3y)/6 = (2z)/6 = (4x - 3y + 2z)/(4 - 6 + 6) = 36/4 = 9`
`=> x/1 = y/2 = z/3 = 9`
`=> x = 1*9=9` $\\$ `y = 2*9 = 18` $\\$ `z = 3*9 = 27`
Vậy, `x = 9; y = 18; z = 27`
Các câu còn lại cậu làm tương tự nhé.
a, x/5-y/2
=> 3x/15=2y/4=3x-2y/15-4=44/11=4
+, x/5=4 => x=20
+, y/2=4 => y=8
c, 4x=3y
=> x/3=y/4=x-y=3-4=11/-1=-11
+, x/3=-11 => x=-33
+, y/4=-11 => y=-44
\(4x=3y\Rightarrow x=\dfrac{3}{4}y\)
\(x+y=21\Rightarrow\dfrac{3}{4}y+y=21\Rightarrow\dfrac{7}{4}y=21\Rightarrow y=12\)
\(\Rightarrow x=9\)
\(\left\{{}\begin{matrix}4x=3y\\4x+4y=4\cdot14=56\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}4x=3y\\3y+4y=56\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}4x=3y\\y=8\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=6\\y=8\end{matrix}\right.\)
\(4x=3y=>y=\dfrac{4x}{3}\) thế y vào x+y=14
\(=>x+\dfrac{4x}{3}=14< =>\dfrac{7x}{3}=14=>7x=42< =>x=6\)
\(=>y=\dfrac{4.6}{3}=8\)