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a) \(4x+12:3=40\)
\(4x+4=40\)
\(4x=40-4\)
\(4x=36\)
\(x=36:4\)
\(x=9\)
b) \(2^{x+7}+2017^0=65\)
\(2^{x+7}+1=65\)
\(2^{x+7}=65-1\)
\(2^{x+7}=64\)
\(2^{x+7}=2^6\)
\(x+7=6\)
\(x=6-7\)
\(x=-1\)
a) \(8x+56:14=60\)
\(\Rightarrow8x+4=60\)
\(\Rightarrow8x=56\)
\(\Rightarrow x=\dfrac{56}{8}\)
\(\Rightarrow x=7\)
b) Mình làm rồi nhé !
c) \(41-2^{x+1}=9\)
\(\Rightarrow2^{x+1}=41-9\)
\(\Rightarrow2^{x+1}=32\)
\(\Rightarrow2^{x+1}=2^5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=4\)
d) \(3^{2x-4}-x^0=8\)
\(\Rightarrow3^{2x-4}-1=8\)
\(\Rightarrow3^{2x-4}=9\)
\(\Rightarrow3^{2x-4}=3^2\)
\(\Rightarrow2x-4=2\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
g) \(65-4^{x+2}=2014^0\)
\(\Rightarrow65-4^{x+2}=1\)
\(\Rightarrow4^{x+2}=64\)
\(\Rightarrow4^{x+2}=4^3\)
\(\Rightarrow x+2=3\)
\(\Rightarrow x=1\)
i) \(120+2\left(4x-17\right)=214\)
\(\Rightarrow2\left(4x-17\right)=214-120\)
\(\Rightarrow2\left(4x-17\right)=94\)
\(\Rightarrow4x-17=47\)
\(\Rightarrow4x=47+17\)
\(\Rightarrow4x=64\)
\(\Rightarrow x=16\)
a: \(8x+56:14=60\)
=>8x+4=60
=>8x=60-4=56
=>x=56/8=7
b: \(5^{2x-3}-2\cdot5^2=5^2\cdot3\)
=>\(5^{2x-3}=5^2\cdot3+2\cdot5^2=5^3\)
=>2x-3=3
=>2x=6
=>x=3
c: \(41-2^{x+1}=9\)
=>\(2^{x+1}=41-9=32\)
=>x+1=5
=>x=4
d: \(3^{2x-4}-x^0=8\)
=>\(3^{2x-4}-1=8\)
=>\(3^{2x-4}=8+1=9\)
=>2x-4=2
=>2x=6
=>x=3
g: \(65-4^{x+2}=2014^0\)
=>\(65-4^{x+2}=1\)
=>\(4^{x+2}=65-1=64\)
=>x+2=3
=>x=1
i: 120+2(4x-17)=214
=>2(4x-17)=214-120=94
=>4x-17=94/2=47
=>4x=64
=>\(x=\dfrac{64}{4}=16\)
4^(4x-5)-1=65
4^(4x-5)=65-1
4^(4x-5)=64
4^(4x-5)=4^3 (vì 4>0)
=>4x-5=3
=>4x=3+5
=>4x=8
=>x=8:4
=>x=2
Vậy x=2
(4x - 28) : 2 = 9² - 65
(4x - 28) : 2 = 81 - 65
(4x - 28) : 2 = 16
4x - 28 = 16 . 2
4x - 28 = 32
4x = 32 + 28
4x = 60
x = 60 : 4
x = 15
(4\(x\) - 28) : 2 = 92 - 65
(4\(x\) - 28 ) : 2 = 81 - 65
(4\(x\) - 28) : 2 = 16
4\(x\) - 28 = 16 x 2
4\(x\) - 28 = 32
4\(x\) = 32 + 28
4\(x\) = 60
\(x\) = 60 : 4
\(x\) = 15
a) \(19.43+\left(-20\right).43-\left(-40\right)\)
\(=43.\left(19-20\right)+40\)
\(=-43+40\)
\(=-3\)
b) \(6^7:6^5+3.3^2-2021^0\)
\(=6^2+3^3-1\)
\(=36+27-1\)
\(=62\)
c) \(465+\left[\left(-38\right)+\left(-465\right)\right]-\left[12-\left(-42\right)\right]\)
\(=465-38+\left(-465\right)-12-42\)
\(=-92\)
\(4^{x+1}+4^0=65\)
\(4^{x+1}+1=65\)
\(4^{x+1}=65-1\)
\(4^{x+1}=64\)
\(4^{x+1}=4^3\)
=> X+1=3
x =2
Vậy x=2
\(4^{x+1}\) + \(4^0\) = 65
\(\Rightarrow\) \(4^{x+1}\) + 1 = 65
\(\Rightarrow\) \(4^{x+1}\) = 65 - 1 = 64 = \(4^3\)
\(\Rightarrow\) x + 1 = 3
\(\Rightarrow\) x = 3 - 1 = 2
Vậy x = 2 .