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a, \(4^7.3^4.9^6:6^{13}\)
\(=\left(2^{14}.3^4.3^{12}\right):\left(2^{13}.3^{13}\right)\)
\(=2^{14}:2^{13}.3^{16}:3^{13}\)
\(=2.3^3=54\)
b, \(2^3.3^2-5^{16}:25^7\)
\(=72-5^{16}:5^{14}\)
\(=72-5^2=47\)
4^7.3^4.9^6:6^13=4^7.3^4.(3^2)^6:6^13
=4^7.3^16:3^13.2^13
=(2^2)^7.3^16:3^13.2^13
=2^14.3^16:3^13.2^13
=2.3^3
=54
Ta có : \(C=\dfrac{4^6.3^4.9^5}{6^{12}}=\dfrac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{\left(2.3\right)^{12}}=\dfrac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=3^{4+10-12}=3^2=9\)
\(\left(4096.81.729\right):2176782336\)
\(\left(331776.729\right):2176782336\)
\(\left(241864704\right):2176782336\)
\(\frac{4^6.3^4.9^3}{6^{12}}=\frac{2^{12}.3^4.3^6}{2^{12}.3^{12}}=\frac{2^{12}.3^{10}}{2^{12}.3^{12}}=\frac{1}{3^2}=\frac{1}{9}\)
B = 4^9.36+64^4
16^4.100
B = 2^20.(9+16)
2^18.5^2
B = 2^20.5^2
2^18.5^2
B = 2^2
B = 4
D = 4^6.3^4.9^5
6^12
D = 2^12.3^4.9^5
2^12.3^12
D = 2^12.3^14
2^12.3^12
D = 3^2
D = 9
\(\frac{4^9.36+64^4}{16^4.100}=\frac{4^{10}\left(9+8\right)}{4^{10}.25}=\frac{17}{25}\)
\(3^3.3^x-1=26\)
=> \(3^{3+x}=26+1=27\)
=> \(3^{3+x}=3^3\)
=> \(3+x=3\)
=> \(x=3-3=0\)
Vậy \(x\in\left\{0\right\}\)