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a) \(6,5+1,2+3,5-5,2+6,5-4,8\)
\(=6,5+1,2+3,5+6,5-5,2-4,8\)
\(=\left(6,5+3,5+6,5\right)+1,2-\left(5,2+4,8\right)\)
\(=16,5+1,2-10\)
\(=17,7-10\)
\(=7,7.\)
b) \(\left(-4,3.1,1+1,1.4,5\right):\left(-0,5:0,05+10,01\right)\)
\(=\left\{1,1.\left[\left(-4,3\right)+4,5\right]\right\}:\left[\left(-10\right)+10,01\right]\)
\(=\left(1,1.0,2\right):0,01\)
\(=0,22:0,01\)
\(=22.\)
c) \(\left(6,7+5,66-3,7+4,34\right).\left(-76,6.1,2+7,66.12\right)\)
\(=\left[\left(5,66+4,34\right)+\left(6,7-3,7\right)\right].\left[7,66.\left(-10\right).1,2+7,66.12\right]\)
\(=\left[10+3\right].\left[7,66.\left(-12\right)+7,66.12\right]\)
\(=13.\left\{7,66.\left[\left(-12\right)+12\right]\right\}\)
\(=13.0\)
\(=0.\)
Chúc bạn học tốt!
1) Tính nhanh
a) \(6,5+1,2+3,5-5,2+6,5-4,8\)
\(=\left(6,5+3,5\right)-\left(5,2+4,8\right)+\left(1,2+6,5\right)\)
\(=10-10+7,7\)
\(=7,7\)
Bài 1:
a: \(=\dfrac{\left(-4.3+1.1\cdot45\right)}{-10+10.01}=\dfrac{49.5-4.3}{0.01}=4520\)
c: \(=\left(3+10\right)\cdot\left[7.66\left(-10\cdot1.2+12\right)\right]\)
=0
a/ \(6,5+1,2+3,5-5,2+6,5-4,8\)
\(=\left(6,5+3,5+6,5\right)+1,2-\left(5,2+4,8\right)\)
\(=16,5+1,2-10\)
\(=17,7-10=7,7\)
b/ \(\left(-4,3.1,1+1,1.4,5\right):\left(-0,5:0,05+10,01\right)\)
\(=1,1\left(-4,3+4,5\right):\left(-10+10,01\right)\)
\(=1,1.0,2:0,01\)
\(=1,1.20=22\)
c/ \(\left(6,7+5,66-3,7+4,34\right).\left(-76,6.1,2+7,66.12\right)\)
\(=\left[\left(5,66+4,34\right)+\left(6,7-3,7\right)\right]\left[7,66.\left(-10\right).1,2+7,66.12\right]\)
\(=\left(10+3\right).\left[7,66\left(-12\right)+7,66.12\right]\)
\(=13.0=0\)
\(\text{6,5+ 1,2+3,5-5,2+6,5-4,8}=\left(6,5+3,5\right)+\left(-5,2-4,8\right)+\left(1,2+6,5\right)\)
=10-10+7,7=7,7
\(\text{(-4,3.1,1+1,1.4,5): (-0,5:0,05+10,01)}=\dfrac{1,1.\left(-4,3+4,5\right)}{-10+10,01}=\dfrac{0,22}{0,01}=22\)
\(\text{(6,7+5,66-3,7+4,34). (-76,6.1,2+7,66.12)}\)
=(6,7+5,66-3,7+4,34)(-76,6.1,2+76,6.1,2)=0
\(a.6,5+1,2+3,5-5,2+6,5-4,8
\)
\(=\left(6,5+3,5\right)+\left(1,2+6,5\right)-\left(5,2+4,8\right)\)
\(=10+7,7-10\)
\(=\left(10-10\right)+7,7\)
\(=0+7,7=7,7\)
a) 0, 2 + |x - 2, 3 | = 1, 1
=> | x - 2 , 3 | = 1,1 - 0, 2
=> | x - 2,3 | = 0, 9
=> x - 2 , 3 = 0, 9 hoặc x - 2 , 3 = - 0 , 9
=> x = 0, 9 + 2, 3 hoặc x = - 0, 9 + 2 , 3
=> x = 3 , 2 hoặc x = 1, 4
b) - 1 + | x + 4 , 5 | = - 6, 2
=> | x + 4 , 5 | = - 6 , 2 - ( - 1 )
=> | x + 4, 5 | = - 5 , 2 ( vô lí )
Vậy không có x thỏa mãn
tick tớ nha bạn !
A=( -4,3 . 1,1 + 1,1 . 4,5 ) : ( -0,5 : 0,05 + 10,01 )
A= [1,1.(-4.3+4,5)] : (-10+10,01)
A=(1,1 . 0,2): 0,01
A=0,22 : 0,01
A=22
\(\left(-4,3.1,1+1,1.4,5\right):\left(-0,5:0,05+10,01\right)\)
\(=\left[1,1\left(-4,3+4,5\right)\right]:\left(-10+10,01\right)\)
\(=\left[1,1.0,2\right]:0,01\)
\(=0,22:0,01\)
\(=22\)