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4/15 + 8/13 + 11/5 + 5/13
= (4/15 + 11/5) + (8/13 + 5/13)
= (4/15 + 33/15) + 13/13
= 37/15 + 1
= 52/15.
\(\frac{4}{15}+\frac{8}{13}+\frac{11}{15}+\frac{5}{13}\)
\(=\left(\frac{4}{15}+\frac{11}{15}\right)+\left(\frac{8}{13}+\frac{5}{13}\right)\)
\(=\frac{15}{15}+\frac{13}{13}\)
\(=1+1\)
\(=2\)
Mình sửa đề luôn cho bạn rồi đó. né.
\(\frac{4}{15}+\frac{8}{13}+\frac{11}{15}+\frac{5}{13}\)
\(=\left(\frac{4}{15}+\frac{11}{15}\right)+\left(\frac{8}{13}+\frac{5}{13}\right)\)
\(=\frac{15}{15}+\frac{13}{13}\)
\(=1+1\)
\(=2\)
Chúc bạn học tốt nha !!!
\(\frac{4}{15}+\frac{8}{13}+\frac{11}{15}+\frac{5}{13}\)
\(=\left(\frac{4}{15}+\frac{11}{15}\right)+\left(\frac{8}{13}+\frac{5}{13}\right)\)
\(=1+1\)
\(=2\)
4/15 + 8/13 + 11/15 + 5/13
= ( 4/15 + 11/15 ) + ( 8/13 + 5/13 )
= 15/15 + 13/13
= 1 + 1
=2
\(\frac{4}{15}+\frac{8}{13}+\frac{11}{5}+\frac{5}{13}\)
\(=\left(\frac{4}{15}+\frac{11}{15}\right)+\left(\frac{8}{13}+\frac{5}{13}\right)\)
\(=1+1\)
\(=2\)
2,07 + 4,15 + 17,93 + 5,85
= (2,07 + 17,93) + (4,15 + 5,85)
= 20 + 10
= 30
Ta có: \(\dfrac{5}{9}+\dfrac{13}{7}+\dfrac{15}{3}+\dfrac{8}{7}+\dfrac{4}{9}+\dfrac{11}{13}\)
\(=\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\left(\dfrac{13}{7}+\dfrac{8}{7}\right)+5\dfrac{11}{13}\)
\(=9+\dfrac{11}{13}\)
\(=\dfrac{128}{13}\)
1.3.77−1+3.7.99−3+7.9.1313−7+9.13.1515−9+\frac{19-13}{13.15.19}+13.15.1919−13
=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}=1.31−3.71+3.71−7.91+7.91−9.131+9.131−13.151+13.151−15.191
=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}=1.31−15.191=28595−2851=28594
b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)b,=61.(1.3.76+3.7.96+7.9.136+9.13.156+13.15.196)
làm giống như trên
c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)c,=81.(1.2.31+2.3.41+3.4.51+...+48.49.501)
=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)=161.(1.2.32+2.3.42+3.4.52+...+48.49.502)
=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)=161.(1.2.33−1+2.3.44−2+3.4.55−3+...+48.49.5050−48)
=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)=161.(1.21−2.31+2.31−3.41+3.41−4.51+...+48.491−49.501)
=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}=161.(21−24501)=161.(24501225−24501)=4900153
d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)d,=75.(1.5.87+5.8.127+8.12.157+...+33.36.407)
=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)=75.(1.5.88−1+5.8.1212−5+8.12.1515−8+...+33.36.4040−33)
=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)=75.(1.51−5.81+5.81−8.121+8.121−12.151+...+33.361−36.401)
=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}=75.(51−14401)=75.(1440288−14401)=28841
P/S: . là nhân nha
- số số hạng của tổng là:
(15-1):2+1=8(số hạng)
Tổng trên có giá trị là:
(15+1).8:2=64
-số số hạng của tổng là:
(16-2):2+1=8(số hạng)
Tổng trên có giá trị là:
(16+2).8:2=72
-số số hạng của tổng là:
(22-1):3+1=8(số hạng)
Tổng trên có giá trị là:
(22+1).8:2=92
1+3+5+7+9+11+13+15=(1+15)+(3+13)+(5+11)+(7+9)=16x4=64
1+5+9+13+17+21+25+29+33+37=(1+37)+(5+33)+(9+29)+(13+25)+(17+21)=38x5=190
\(\frac{4}{15}+\frac{8}{13}+\frac{11}{5}+\frac{5}{13}=\left(\frac{4}{15}+\frac{11}{5}\right)+\left(\frac{8}{13}+\frac{5}{13}\right)\)\(=\frac{37}{15}+1=\frac{52}{15}\)
#Kochou-Shinobu
4/15 + 8//13 + 11/5 + 5/13 = (4/5 + 11/5 ) + ( 8/13 + 5/13 ) = 37/15 + 1 = 52/15.
#Songminhtử