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a, 2\(^x\) - 15 = 17
2\(^x\) = 17 + 15
2\(^x\) = 32
2\(^x\) = 25
\(x\) = 5
b, (2\(x\) - 11)5 = 24.32 + 99
(2\(x\) - 11)5 = 16.9 + 99
(2\(x\) - 11)5 = 144 + 99
(2\(x\) - 11)5 = 243
(2\(x\) - 11)5 = 35
2\(x\) - 11 = 3
2\(x\) = 3 + 11
2\(x\) = 14
\(x\) = 14: 2
\(x\) = 7
c, \(x^{10}\) = 1\(^x\)
\(x^{10}\) = 1
\(x^{10}\) = 110
\(\left[{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\)
\(x\) \(\in\) { -1; 1}
A) \(...\Rightarrow2^x=32=2^5\Rightarrow x=5\)
B) \(...\Rightarrow\left(2x-11\right)^5=243=3^5\)
\(\Rightarrow2x-11=5\Rightarrow2x=16\Rightarrow x=8\)
C) \(...\Rightarrow x^{10}=1=x^0\Rightarrow x=1\)
a, 5 3 + 3 4 + 4 . 2 + 27 - 3 : 4
= 125+170+6
= 301
b, 124 : 3 2 . 7 - 1 10 + 24 : 5 2
= 124:[9.7–(1+24):25]
= 124 : [63–25:25]
= 124:62
= 2
c, 245 - 4 16 : 8 + 2 4 . 3 2 - 9
= 245–4[2+2.27]
= 245–4.45
= 29
d, 375 : 5 3 - 3 8 : 3 6 - 2 . 2 3
= 375 : 125 – (9–16)
= 3–9+16
= 10
mình nghĩ là đề như vậy:
\(\frac{24}{8.16}-\frac{40}{16.24}+\frac{56}{24.32}-\frac{72}{32.40}=\frac{8+16}{8.16}-\frac{16+24}{16.24}+\frac{24+32}{24.32}-\frac{32+40}{32.40}\)
\(=\frac{8}{8.16}+\frac{16}{8.16}-\frac{16}{16.24}-\frac{24}{16.24}+\frac{24}{24.32}+\frac{32}{24.32}-\frac{32}{32.40}-\frac{40}{32.40}\)
\(=\frac{1}{16}+\frac{1}{8}-\frac{1}{24}-\frac{1}{16}+\frac{1}{32}+\frac{1}{24}-\frac{1}{40}-\frac{1}{32}\)
\(=\frac{1}{8}-\frac{1}{40}=\frac{1}{10}\)
Em kiểm tra lại đề bài, \(3^x+3^{x+2}+3^{x+2}\) hay \(3^x+3^{x+1}+3^{x+2}\)
$\Rightarrow 3^x(1+3+3^2+3^3)=1080$
$\Rightarrow 3^x.40=1080$
$\Rightarrow 3^x=27=3^3$
$\Rightarrow x=3$
a) Ta có 2x + 2x + 1 + 2x + 2 = 56
⇒ 2x ( 1 + 21 + 22 ) = 56
⇒ 2x . 7 = 56
⇒ 2x = 56 : 7 = 8 = 23
Vậy x = 3
b) Ta có 3x + 3x + 2 + 3x + 3 = 111
⇒ 3x ( 1 + 32 + 33 ) = 111
⇒ 3x . 37 = 111
⇒ 3x = 111 : 37 = 3 = 31
Vậy x = 1
Ta có: \(3^x+3^{x+2}+3^{x+3}=3^5\cdot37\)
\(\Leftrightarrow3^x\cdot\left(1+9+27\right)=3^5\cdot37\)
hay x=5
3x-2 -24 . 32 = 32 . 3
<=> 3x-2 -216 = 27
<=> 3x-2 =243
<=> 3x-2 = 35
<=> x-2 = 5
<=> x = 7
\(3^{x-2}-24\cdot3^2=3^2\cdot3\)
\(3^{x-2}-24\cdot9=9\cdot3\)
\(3^{x-2}-216=27\)
\(3^{x-2}=27+216=243\)
\(\Rightarrow3^{x-2}=3^5\)
\(\Rightarrow x-2=5\)
\(\Rightarrow x=5+2=7\)
tk mk nha. ~CHÚC BẠN HỌC TỐT~